Reduction Methods

Reply #20

Maverick — Mon, 24 Jan 2005 01:50:05 GMT

Quote: Originally posted by SirMetro on January 11, 2005Reduction method<===>it's what happens to my wallet whenever I play the lottery.Best laugh I had all day

Reply #19

LANTERN — Mon, 24 Jan 2005 01:39:49 GMT

White Ball 1::: low=1 high=32 ::: eliminate 33-49White Ball 2::: low=2 high=45 ::: eliminate 46-50White Ball 3::: low=6 high=50 ::: eliminate 3-5 and 51White Ball 4::: low=8 high=52 ::: eliminate 4-7White Ball 5::: low=10 high=53 ::: eliminate 5-9If you see that the game has too many balls and so therefore is very hard to make good reductions, or that with your present reduction methods you can't reduce your picks enough and if you also know that no matter what you do, that you are not... [ More ]

Reply #18

hypersoniq — Sun, 23 Jan 2005 18:00:34 GMT

The way I see it, lady luck isn't on my side... I would probably lose anyway, so I am happier being in the game with one ticket and spending $2 (for the power play) than to be holding a fistful of losers.In this way my hobby only sets me back a maximum of $208 a year... and I do occasionally match 3 or the pb and 1 or 2, keeps it interesting.If I do win I generally add another line or 2 the next draw. one shot, done... that's the plan. If I were to play pick 3 (which I don't) I would play a few... [ More ]

Reply #17

codmander — Sat, 22 Jan 2005 15:57:08 GMT

take 30 draws take each number put a dash mark // next to it then measure take some of the shortest some of the longest and some average and mixn match em

Reply #16

Fenix — Mon, 17 Jan 2005 03:05:09 GMT

Quote: Originally posted by hypersoniq on January 16, 2005 I still just play one ticket.... Wow , you are a really optimistic person Hypersoniq. Im looking presently for a good system containing more than one combination, since for a good win in my opinion playing just one line someone gotta count on a sparkling lucky star , and my lucky star is not that colorful for some period of time however, I love it since it is probably a bit more lazy than usually..

Reply #15

hypersoniq — Sun, 16 Jan 2005 16:33:09 GMT

definitely not something to make you buy more tickets, but something to use as a loose guideline... I still just play one ticket.... still no jackpot.I use excel for keeping track of the draws, the white balls are separated into separate columns so it is easy to check observed ranges at a glance. I have the same type of sheet for the 6/49 Match6 (for kicks, I don't play it tho, doing my part to protest PA low jackpot $2 tickets...) and it is the same thing, the draw history when sorted has a def... [ More ]

Reply #14

Fenix — Fri, 14 Jan 2005 11:22:08 GMT

Quote: Originally posted by johnph77 on January 14, 2005Fenix -Powerball is a 5/53+1/42 game. The five balls are white, the bonus ball is red.gljohnThat means Hypersonic was thinking about positioning...well, in my opinion it may work but not necessary...have seen all winning numbers from the last two decades with most of them from the last decade, which may be a fine occurrence for a patient trapper . Not necessary means wouldn't advice someone to try it with some more tickets than usual...es... [ More ]

Reply #13

johnph77 — Fri, 14 Jan 2005 11:04:50 GMT

Fenix -Powerball is a 5/53+1/42 game. The five balls are white, the bonus ball is red.gljohn

Reply #12

Fenix — Fri, 14 Jan 2005 10:20:06 GMT

Quote: Originally posted by hypersoniq on January 13, 2005Actually, some reduction that leads to a large data set of possible numbers could be used as boundaries for your own smart QP ... I think that's what RJOh's basic program does...let's look to the powerball for an example...Current absolute observed positional boundaries...White Ball 1::: low=1 high=32 ::: eliminate 33-49White Ball 2::: low=2 high=45 ::: eliminate 46-50White Ball 3::: low=6 high=50 ::: eliminate 3-5 and 51White Ball... [ More ]

Reply #11

hypersoniq — Fri, 14 Jan 2005 01:05:04 GMT

Actually, some reduction that leads to a large data set of possible numbers could be used as boundaries for your own smart QP ... I think that's what RJOh's basic program does...let's look to the powerball for an example...Current absolute observed positional boundaries...White Ball 1::: low=1 high=32 ::: eliminate 33-49White Ball 2::: low=2 high=45 ::: eliminate 46-50White Ball 3::: low=6 high=50 ::: eliminate 3-5 and 51White Ball 4::: low=8 high=52 ::: eliminate 4-7White Ball 5::: lo... [ More ]

Reply #10

Rick G — Wed, 12 Jan 2005 18:03:06 GMT

I agree with Todd....use the most effective reduction methods in your aresenal until you have a manageable amount of picks that fits your budget.I have a daily and/or weekly budget and will do any reduction it takes to stay close to that budget.

Reply #9

Todd — Wed, 12 Jan 2005 17:24:22 GMT

Quote: Originally posted by SirMetro on January 11, 2005Reduction method<===>it's what happens to my wallet whenever I play the lottery.Sir Metro Good one

Reply #8

RJOh — Wed, 12 Jan 2005 17:03:55 GMT

If you want to know how well your reduction system is working, you simply check a copy of the file before reduction and after reduction with the drawing results and adjust your reduction methods accordingly.RJOh

Reply #7

lottoarchitect — Wed, 12 Jan 2005 16:06:20 GMT

Quote: Originally posted by JKING on January 11, 2005Todd,What I'm after here is -What's the most effective way to filter/reduce combinations. Is it by using many or just a few to achieve the amount of reduction your looking for. Which method gives you the greatest reward with the least pitfalls.A follow up question to all this is- Can you get a meaningful amount of reductions without exceeding a 100%+ error ratio?You cannot exceed 100% error neither fall below 0% error. The only way to get 0% e... [ More ]

Reply #6

SirMetro — Tue, 11 Jan 2005 22:09:26 GMT

Reduction method<===>it's what happens to my wallet whenever I play the lottery.Sir Metro

Reply #5

Todd — Tue, 11 Jan 2005 16:05:26 GMT

Quote: Originally posted by JKING on January 11, 2005Todd, What I'm after here is -What's the most effective way to filter/reduce combinations. Is it by using many or just a few to achieve the amount of reduction your looking for. Which method gives you the greatest reward with the least pitfalls.A follow up question to all this is- Can you get a meaningful amount of reductions without exceeding a 100%+ error ratio?Just by the nature of reductions, you are introducing error to the game. You are... [ More ]

Reply #4

JKING — Tue, 11 Jan 2005 15:38:58 GMT

Todd, What I'm after here is -What's the most effective way to filter/reduce combinations. Is it by using many or just a few to achieve the amount of reduction your looking for. Which method gives you the greatest reward with the least pitfalls.A follow up question to all this is- Can you get a meaningful amount of reductions without exceeding a 100%+ error ratio

Reply #3

LANTERN — Mon, 10 Jan 2005 15:54:24 GMT

Yes, I do think that it's better to improve a few reduction methods than to use too many, because yes, too many reduction methods do give your prediction more chances to fail.There of course, as Todd says, have to be a balance of all factors involved.

Reply #2

lottoarchitect — Mon, 10 Jan 2005 15:16:13 GMT

Your overall success with 5 different reductions will be 0.98^5=0.9039=90.39% so they seem to be equal in effectiveness with the 1 reduction method. In general, it is better to try improving fewer reduction methods than using many with higher success ratio.

Reply #1

Todd — Mon, 10 Jan 2005 15:08:33 GMT

Which reduction methods are you referring to?With most reduction methods I have used, another variable that needs to be considered is your budget - how many tickets you want to play.

Reduction Methods

JKING — Mon, 10 Jan 2005 04:29:31 GMT

Is it better to use 5 reductons with 98% accurracy or 1 reduction with 90.4% accurracy?Does the multi reduction method give more eliminated combinations or does it give more chances for your prediction to go wrong