math problem worth a million can you answer it

Reply #25

bud1 — Wed, 07 Mar 2007 13:18:09 GMT

hey lotteryman99 i know your almost there,wont be long,bud1

Reply #24

Pogo — Mon, 05 Mar 2007 03:16:21 GMT

HyperSonic meant:

Set1 set2 set3 set4

22 18 12 18

22 24 12 24

24 18 16 18

Root Sums:

Set1 set2 set3 set4

4 9 3 9

4 6 3 6

6 9 7 9

Notice Patterns:

9's - form a box

4's - 1st pillar

3's - 2nd pillar

what I thought is suppose to be 7 6 combo going diagonally up from left to right (assuming the lower left number is incorrect)

Which is why I asked earlier if that was the cor... [ More ]

Reply #23

hypersoniq — Sat, 03 Mar 2007 17:33:09 GMT

set1 set2 set3 set4

7654 1593 4062 3951

7159 7395 4062 9258

9357 1098 8260 3951

More Info

1)Set 1

3rd digit is the same distance from the 2nd and 4th

examples

7654

6=5+1

4=5-1

7159

1=5-4

9=5+4

9357

3=5-2

7=5+2

2)Set 3

digit1 - digit2 + digit4 = digit3

examples

4062

4-0+2=6 (4062 appears twice)

8260

8-2+0=6

Reply #22

hypersoniq — Sat, 03 Mar 2007 17:23:07 GMT

set1 set2 set3 set4

7654 1593 4062 3951

7159 7395 4062 9258

9357 1098 8260 3951

Known so far

1) 3rd digit of each set is the same for all 3 (5,9,6,5)

2) 2nd number in third row of sets 1,2,3 equal 2nd number in 2nd row of sets 2,3,4, respectively.

3) each set has a repeating number in the first column (7's, 1's, 4's and 3's)

4) set 3 and set 4 have 2 duplicate rows (4062, 3951)

5)Sums all even

Set1 set2 set3 set4

22 18 12 18

22 24... [ More ]

Reply #21

Pogo — Sat, 03 Mar 2007 15:20:32 GMT

7654 1593 4062 3951

7159 7395 4062 9258

9357 1098 8260 3951

3rd column in each set is the same number is significant because it is in all the sets. -POGO

Reply #20

ejwmoney — Sat, 03 Mar 2007 14:27:03 GMT

Sorry, I was not completely clear. The last number in row 1 of each set is 1 less than the last number in row 1 of the prior set. Lottoman, does this give us 2 things we now know?

7654 1593 4062 3951

7159 7395 4062 9258

9357 1098 8260 3951

Reply #19

ejwmoney — Sat, 03 Mar 2007 14:25:22 GMT

The last number in row 1 of each set is 1 less than. Lottoman, does this give us 2 things we now know?

7654 1593 4062 3951

7159 7395 4062 9258

9357 1098 8260 3951

Reply #18

Pogo — Sat, 03 Mar 2007 02:21:01 GMT

set1 set2 set3 set4

7654 1593 4062 3951

7159 7359 4062 9258

9357 1098 8260 3951

All these numbers have a certain pattern, but the pattern won't make sense unless the 3rd number in set 1 changes to something like 6307, 9097, 9187, 9277, 9367, etc. If indeed you have made a mistake on number 3 in set 1. I might have some info for you. Let me know, -POGO

Reply #17

Blackapple — Tue, 06 Feb 2007 12:40:27 GMT

Info and history is power

What were circumstances

when these numbers

were chosen.

more info.

Where 294 from?

Is there more

******************

in this number the three digit number was 294 added total is 15

Reply #16

lotteryman99 — Sun, 04 Feb 2007 23:37:39 GMT

each set is an example of the way the system figured. from one set predict with accutacy one digit in any spot then the next set predict one digit in a spot it must be in the correct spot one set at a time, each set represnts a digt of the next nymber to play. i would explain more how it works except that would put you in the same thanking as me, i am looking for a diffrent view, this system is all math and if you look closely you will see they all have the same make up in there figures.

Reply #15

ejwmoney — Sat, 03 Feb 2007 18:43:13 GMT

lotteryman99,

Not sure what you are asking. Are you looking for the next spot of each number in the next set? Although, each draw is theoretically random, there are patterns. And patterns can have multiple conditions associated with them(ex. If A then 1 or If B then 2)

Please clarify what you mean when you say find the proper spot of any digit in each row...

Reply #14

lotteryman99 — Mon, 29 Jan 2007 01:46:53 GMT

thanks everyone but i believe the answer is no answer because all systems and numbers are randon

Reply #13

retxx — Wed, 24 Jan 2007 04:08:22 GMT

my question is how it relates to keno peaked my interest greatly if you could explain that. thanks hope someone solves your problem. looks quite interesting.

Reply #12

winsumloosesum — Tue, 23 Jan 2007 21:14:46 GMT

LM99,

This was your post 294 = 15

I just asked the question.

Could you explain how you get the 4 sets of 4 digit numbers??

winsum

Reply #11

lotteryman99 — Tue, 23 Jan 2007 19:02:33 GMT

is this a question or a fact that the third digit is always the root sum

Reply #10

lotteryman99 — Tue, 23 Jan 2007 18:56:25 GMT

is this a question or a fact that the third digit of each set is the root sum

Reply #9

winsumloosesum — Mon, 22 Jan 2007 20:05:56 GMT

The 3rd digit of each four number combination is always the root sum??

What do the rest of the numbers represent?

Thanks

Reply #8

lotteryman99 — Mon, 22 Jan 2007 19:48:18 GMT

the constant digits that you are seeing are the added total of the three digit number in that case

more info.

in this number the three digit number was 294 added total is 15

the five is the total

7654

7159

9357

Reply #7

lotteryman99 — Mon, 22 Jan 2007 19:18:52 GMT

four4me

the odd and even are the mirror to each other this doubles the amount of numbers that one would have to play odd and even on each one would go from 1 number to 16 and ect.

Reply #6

winsumloosesum — Mon, 22 Jan 2007 19:16:42 GMT

Ok that's what I thought.

Does each 4 digit number in each set represent something?

4062 is listed twice in set 3

3951 is listed twice in set4

5 s constant in the 3rd position of each combination in set 1

9 's set 2

6 s set 3

5 s

Reply #5

lotteryman99 — Mon, 22 Jan 2007 19:15:45 GMT

i could tell you what all this means but if i did that i would be putting you on the same course of thought that i am at what i need is a new look at it and a new approch i have been toying with this for years and i understand what ever digit means.. it all leads to stright 3 digit and stright 4 digits, lotto numbers keno and the works.

Reply #4

four4me — Mon, 22 Jan 2007 19:14:14 GMT

if you are using an even number of digits in your wheel/system try using and odd number of digits.

many times i had this problem wheeling even amounts of digits i continuously get repeat

numbers. Using an odd amount solved it for me.

Reply #3

lotteryman99 — Mon, 22 Jan 2007 19:07:04 GMT

look in the last row in each set of numbers (set 1 for example)bottom set of numbers, the second digit of the four digits in that row will be in the second spot of the middle set

7654 1593 4062 3951

7159 7395 4062 9258

9357 1098 8260 3951

Reply #2

truecritic — Mon, 22 Jan 2007 19:01:45 GMT

Yes, if you could explain by way of an example that would help.

Reply #1

winsumloosesum — Mon, 22 Jan 2007 18:25:25 GMT

LM99,

Can you explain The second digit of the last row always lands in the second spot of the middle row ?

Thanks

math problem worth a million can you answer it

lotteryman99 — Mon, 22 Jan 2007 17:26:03 GMT

i have this problem i worked a math system out and and i am down to the finial part and can not get the answer. it involves a numbers system of math, it all lays together and i need to know one thing there is the problem example and i need one digit in any correct spot of each 4 sets if i could do that i could hit any number in any lottery. can you help

set1 set2 set3 set4

7654 1593 4062 3951

7159 7359 4062 9258

9357 1098 8260 3951

each one o... [ More ]