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		<title>Two Groups of Ten -- Mega Attempt</title>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/174702/1027759</link>
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			<pubDate>Thu, 08 May 2008 23:26:20 GMT</pubDate>
			<dc:creator>Hans</dc:creator>
			<description><![CDATA[<p>Group 1<br /><br />02 12 42 06 36 16 24 14 34 07<br /><br />02 32 12 06 36 16 24 14 34 07<br /><br />32 12 42 26 36 16 04 14 34 27<br /><br />02 32 12 26 36 16 24 04 14 34<br /><br />Group 2<br /><br />46 47 23 22 44 45 52 48 53 54</p>]]></description>
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			<title>Two Groups of Ten -- Mega Attempt</title>
			<link>https://www.lotterypost.com/thread/174702</link>
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			<pubDate>Thu, 08 May 2008 22:37:02 GMT</pubDate>
			<dc:creator>kjs703</dc:creator>
			<description><![CDATA[<p>Greetings:<br /><br />There have been several discussions (topics) to wheel the Jackpot using two groups of Ten Numbers. Now if I understand properly -- if only two or three numbers match in each group, then this system will be able to predict the Jackpot (or wheel it). So I propose a challenge similar to MadDogs for the next MEGA Draw (Friday 9th) ... No Bonus Balls please.....<br /><br />Let&#x27;s see if anyone can reach the two to three per group.....<br /><br />=======================<br /><br />Group 1: 3-6-12-22-24-28-32-35... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/174702">More</a>&#xa0;&#x5d;</p>]]></description>
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