<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/">
	<channel>
		<title>How are odds calculated?</title>
		<link>https://www.lotterypost.com/thread/201322</link>
		<atom:link href="https://www.lotterypost.com/rss/topic/201322" rel="self" type="application/rss+xml" />
		<description>Lottery Post Forum Topic: How are odds calculated?</description>
		<dc:language>en-us</dc:language>
		<generator>Lottery Post RSS Generator</generator>
		<item>
			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/201322/1466809</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1466809</guid>
			<pubDate>Sun, 22 Nov 2009 05:24:43 GMT</pubDate>
			<dc:creator>rcbbuckeye</dc:creator>
			<description><![CDATA[<p>Thanks RJOh.</p>]]></description>
			<category>rcbbuckeye</category>
		</item>
		<item>
			<title>Reply #11</title>
			<link>https://www.lotterypost.com/thread/201322/1464443</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1464443</guid>
			<pubDate>Thu, 19 Nov 2009 18:39:23 GMT</pubDate>
			<dc:creator>RJOh</dc:creator>
			<description><![CDATA[<p>The number of possible combinations in a pool of 56 numbers are 3819816 but odds are based on possible combinations in the game and when you have 46 bonus numbers the possible combinations are 46 x 3819816 = 175711536.<br /><br />Since there are 46 5of5 combinations with a bonus numbers, when the one winning 5+1 combination is removed/subtracted there are (46-1) 45 5of5 combinations left with 175711536 possible combinations and the odds of having one of them are 175711536 45 = 3904700.8.</p>]]></description>
			<category>RJOh</category>
		</item>
		<item>
			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/201322/1464187</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1464187</guid>
			<pubDate>Thu, 19 Nov 2009 13:46:57 GMT</pubDate>
			<dc:creator>rcbbuckeye</dc:creator>
			<description><![CDATA[<p>That&#x27;s how I know to calculate odds (math is not my strong suite). However, on the MM playslip, the odds of 5+0 are 3,904,701. I have wondered where they come up with that number, instead of 3,819,816.</p>]]></description>
			<category>rcbbuckeye</category>
		</item>
		<item>
			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/201322/1438019</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1438019</guid>
			<pubDate>Thu, 22 Oct 2009 14:21:09 GMT</pubDate>
			<dc:creator>Pogo</dc:creator>
			<description><![CDATA[<p>This isn&#x27;t just for calculating the probability of a win - you can calculate the probability of any numeric occurence with this formula - you just need to know how to use it... Including but not limited to lotto, mortgage, etc. Enjoy - Pogo</p>]]></description>
			<category>Pogo</category>
		</item>
		<item>
			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/201322/1437985</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1437985</guid>
			<pubDate>Thu, 22 Oct 2009 13:33:39 GMT</pubDate>
			<dc:creator>Jack-C</dc:creator>
			<description><![CDATA[<p>It&#x27;s much easier to just look at the back of the playslip</p>]]></description>
			<category>Jack-C</category>
		</item>
		<item>
			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/201322/1437977</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1437977</guid>
			<pubDate>Thu, 22 Oct 2009 13:19:16 GMT</pubDate>
			<dc:creator>bomatt</dc:creator>
			<description><![CDATA[<p>I did it. I made a program in Access that calculates all possible combinations and<br /><br />I made a table of that with each being a record. There are 575757 records.<br /><br />Starting from 01-02-03-04-05 and ending with 35-36-37-38-39.</p>]]></description>
			<category>bomatt</category>
		</item>
		<item>
			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/201322/1419236</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1419236</guid>
			<pubDate>Thu, 01 Oct 2009 19:06:38 GMT</pubDate>
			<dc:creator>Pogo</dc:creator>
			<description><![CDATA[<p>Now for Pick 3&#x27;s Pick 4&#x27;s it&#x27;s easy just how many numbers for how many numbers... 1 out of ten (0 - 9) = 10, then for Pick 3 it would be P3 = 10^3 = 1000 or all picks (000 - 999), therefore Pick 4 would be P4 = 10^4 = 10000 or all picks (0000 - 9999)... Much easier however you can still use nCr...<br /><br />nCr = 10 (C1) 1 = 10, 10 (C2) 1 = 10, 10 (C3) 1 = 10 - they are totally independent therefore using Boolean model in probability methods would be a logical AND which is multiplying mathematically, t... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/201322/1419236">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Pogo</category>
		</item>
		<item>
			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/201322/1419218</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1419218</guid>
			<pubDate>Thu, 01 Oct 2009 18:56:13 GMT</pubDate>
			<dc:creator>Pogo</dc:creator>
			<description><![CDATA[<p>Most of the Pick 5&#x27;s, 6&#x27;s, MM, PB, etc. can be calculated using a simple nCr function on a calculator or excel which means from n choose r does this nCr= n!/(n-r)!*r!<br /><br />This gives you an equation that calculates if you choose r numbers from n available it has x odds...<br /><br />I.E. (For Example) MegaMillions 5 out of 56 = C(56,5) = 56! / 5! (56 - 5)! = 3,819,816 1 out of 46 = 46, therefore 3,819,816 * 46 = 175711536<br /><br />There&#x27;s your outcome... Hope that helps, Pogo</p>]]></description>
			<category>Pogo</category>
		</item>
		<item>
			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/201322/1419188</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1419188</guid>
			<pubDate>Thu, 01 Oct 2009 18:09:13 GMT</pubDate>
			<dc:creator>KY Floyd</dc:creator>
			<description><![CDATA[<p>Where does those odds come from?<br /><br />2 of 5 has 1:9.6 odds.<br /><br />3 of 5 has 1:103 odds<br /><br />Where do they come from?<br /><br />===<br /><br />They come from the multiple ways of having some of the 5 winning numbers. As mentioned above, the order isnt important, but there&#x27;s only 1 chance to have all 5 numbers, so there&#x27;s only 1 winning combination out of the 575,757 possible combinations. There are multiple way to have some, but not all of the winning numbers, so that gives you more than 1 chance in 575,757 of winni... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/201322/1419188">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>KY Floyd</category>
		</item>
		<item>
			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/201322/1417885</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1417885</guid>
			<pubDate>Wed, 30 Sep 2009 14:25:44 GMT</pubDate>
			<dc:creator>johnph77</dc:creator>
			<description><![CDATA[<p>Any given 5-number combination can be drawn in 120 different orders, hence the 1*2*3*4*5 divisor, and the true odds of 1::575,757. For instance, if 01-02-03-04-05 were to be the result of the drawing, the order of the draw could have been 03, 01, 04, 02 and 05; 02, 01, 03, 05 and 04; or any of the other 118 orders available for this set of numbers.<br /><br />For more info:<br /><br />http://www.johnph77.com/math/lo.html<br /><br />No ads, nothing to sell, for informational purposes only.<br /><br />gl<br /><br />j</p>]]></description>
			<category>johnph77</category>
		</item>
		<item>
			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/201322/1417153</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1417153</guid>
			<pubDate>Tue, 29 Sep 2009 17:20:01 GMT</pubDate>
			<dc:creator>Tinker</dc:creator>
			<description><![CDATA[<p>(39*38*37*36*35) / (1*2*3*4*5) = 575757<br /><br />Any other odds I&#x27;m not good at.</p>]]></description>
			<category>Tinker</category>
		</item>
		<item>
			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/201322/1417145</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322/1417145</guid>
			<pubDate>Tue, 29 Sep 2009 17:09:09 GMT</pubDate>
			<dc:creator>Todd</dc:creator>
			<description><![CDATA[<p></p>]]></description>
			<category>Todd</category>
		</item>
		<item>
			<title>How are odds calculated?</title>
			<link>https://www.lotterypost.com/thread/201322</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/201322</guid>
			<pubDate>Tue, 29 Sep 2009 15:02:35 GMT</pubDate>
			<dc:creator>bomatt</dc:creator>
			<description><![CDATA[<p>Cash 3 Cash 4 are easy. 1:1000 odds out of 1000 numbers or 1:10,000<br /><br />But fantasy 5 has 1:575,757 odds for 5 of 5.<br /><br />I thought it was 39*38*37*36*35 which is 69,090,840.<br /><br />Where does those odds come from?<br /><br />2 of 5 has 1:9.6 odds.<br /><br />3 of 5 has 1:103 odds<br /><br />Where do they come from</p>]]></description>
			<category>bomatt</category>
		</item>
	</channel>
</rss>

