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		<title>Solitaire Probability Question</title>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/210286/1581008</link>
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			<pubDate>Wed, 10 Mar 2010 20:40:24 GMT</pubDate>
			<dc:creator>Taipanez</dc:creator>
			<description><![CDATA[<p>i took the total number of hearts remaining over the total number of cards and multiplied across the board<br /><br />13/52 *12/51*11/50*10/49*9/48*8/47=1,235,520/14,658,134,400 or 1 in 11,863.94</p>]]></description>
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			<title>Solitaire Probability Question</title>
			<link>https://www.lotterypost.com/thread/210286</link>
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			<pubDate>Tue, 09 Mar 2010 02:11:22 GMT</pubDate>
			<dc:creator>Hermanus104</dc:creator>
			<description><![CDATA[<p>I was playing solitaire this evening, and the the first six top cards were hearts:<br /><br />H - - - - - -<br /><br />H - - - - -<br /><br />H - - - -<br /><br />H - - -<br /><br />H - -<br /><br />H -<br /><br />S<br /><br />What is the probability of this happening? I multiplied 13 (hearts) x 12 x 11 x 10 x 9 x 8 and divided it by 4 (suits) to get 308,880, but I am not sure if I did this correctly.</p>]]></description>
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