Are the following odds correct?

Reply #12

RJOh — Fri, 21 Oct 2011 04:20:54 GMT

You only need to get it if you want to know it, other wise it doesn't matter.

Reply #11

Jaretzy2jordany — Fri, 21 Oct 2011 04:01:56 GMT

Its nice but i dont get it

Reply #10

nasp — Fri, 30 Sep 2011 21:04:41 GMT

Thanks RJoh

Reply #9

RJOh — Fri, 30 Sep 2011 14:04:53 GMT

You simply figure the number of combinations in the pool size you're using for your wheel and divide that number by the number of combinations in a pool of 49 numbers.

6/18 = 18564

6/20 = 38760

6/24 = 134596

6/30 = 593775

6/40 = 3838380 and etc.

6/49 = 13983816

Reply #8

nasp — Fri, 30 Sep 2011 12:00:53 GMT

I think I found a website that does the calculation automatically. Still, if you know the formula for getting the odds for trapping all 6 numbers in an x amount of numbers in a wheel please let me know.

Spy

Reply #7

nasp — Fri, 30 Sep 2011 11:42:55 GMT

Hi, thanks for replying. Now I get it.

What about a formula for simply getting all six numbers in a chosen wheel? What are the odds lets say of trapping all 6 numbers in a wheel of 20? (not in a single winning line but simply trapping them in the wheel?)

Thank you for your time

Spy

Reply #6

RJOh — Fri, 30 Sep 2011 05:03:16 GMT

There are 8008 possible combinations of 6 in a pool of 16 numbers and you have 840 of them, do the math.

840 8008=.104895105 or ~10

Reply #5

nasp — Thu, 29 Sep 2011 12:43:00 GMT

Thank you for your reply. Since you have 840 chances, your odds of your wheel matching 5 numbers is 64.5 to 1 . How can this be? I am playing a 5 if 5 wheel which guarantees a 5 winning line 100% if I hit 5 numbers in my chosen of 16. So I am essentially playing simply against the odds of getting the 5 numbers in my chosen of 16. Isn't this the case?

Also, is there a chart anywhere that lists the odds of getting all 6 numbers in a wheel of 16,18,20,24 numbers in a 6/49 game?

Than... [ More ]

Reply #4

Stack47 — Thu, 29 Sep 2011 01:24:33 GMT

The odds against matching 5 numbers in 6/49 games is 54.201 to 1. Since you have 840 chances, your odds of your wheel matching 5 numbers is 64.5 to 1.

Even I do the 840/13983816 calculation I get a 6% - which is 4% lower than what CM states.

It's 0.00006 or 0.006%, which happens to be the percentage of all they possible combos you bought.

Reply #3

nasp — Wed, 28 Sep 2011 19:02:07 GMT

Hello, thank you for your reply.Please let me know if the following train of thought is wrong. Lets say I am playing a 6/49 game, I play a 5if5in6 16 numbers 840 lines. At this point, lets say I hit all 6 numbers in my wheel of 16 and I already have a 5# hit in one line. What will be the odds of that 6th number landing in that winning line? I don't think it would be 840/ 13,983,816, as I already have a 5# hit. This means I need the 6th number to land in one of the 840 lines, so that would be 1in... [ More ]

Reply #2

RJOh — Wed, 28 Sep 2011 18:07:27 GMT

If you were playing a 5/16 game then everything you said would be true but chances are you're playing a 5/39 game so you have to figure all 39 numbers when you calculate odds. If you have all 5 winning numbers in your 16 number pool then it makes no difference.

A 5/39 game have 575,757 possible combinations and with a 5/16 wheel you're covering 4,368 of those combinations and hoping one or more of them will have 3 or more of the winning numbers. Also you odds of have all 5 winning numbers in... [ More ]

Reply #1

Todd — Wed, 28 Sep 2011 13:36:00 GMT

Are the following odds correct?

nasp — Wed, 28 Sep 2011 09:45:07 GMT

Hello,

If playing a 5if5 100% in 16 numbers wheel, CM in the detailed report says that there is a 10.4% of all numbers landing in one line. My question is, are really the odds 10 in 100 or 1 in 10 that all 6 numbers will land in one line? If this is the case, this would seem a good wheel for a group play.

Also, is there a chart that states the odds of getting all 6 numbers in a 14,16 etc number wheel?

Thanks

Spy