lottery 39/5

Reply #49

dr san — Thu, 21 Jun 2012 13:22:04 GMT

Hello, this system allows variation example 17-39 forming pair

We have 253 pairs, the 4th and 5th position then only missing the first three

Example = 0_ 0_ 0_ 17 39, only your own pair may give indications of the forecast

Or see froma ao of 000 or 233 etc do not come out of each pair after just missing the three endings that are possible to one million times one repeats

Reply #48

dr san — Tue, 19 Jun 2012 14:30:33 GMT

Hello, for a lottery 39/5 we need to be 100% 741 pairs but I managed

In 99% 163 leveraging pairs can confirm, that is finding the apr to oproximo

39/5 draw within, the pair as 163 references or fixed, give indications which

2224 0001 ... of possible 37, which one example eescolheu inside of 163 the pair

17 23, all that training has. 1.2 filter this inside, here the number 23 can be from 5 {position,

Here are the pairings in 99% = 163

01 02

01 03

01 09

01 15

01 14

Reply #47

dr san — Sat, 16 Jun 2012 12:45:00 GMT

Hello, lottery 39/5 after setting the fixed number of the last position in the limit from 27 to 39 Example 37 the number will be used as fixed, but it can be used as To predict the formations 000.1222, ... etc, get some 200 or three hundred drawings And to see inside the 37 groups (000-3333) to see what is not out yet, example 200 Draws the fixed number 37 not out with training, 1,2,2,4, find the limit of the sweepstakes It is essential, and also endings 0-9, see the set that did not go with the... [ More ]

Reply #46

dr san — Tue, 12 Jun 2012 16:14:14 GMT

Hello, this is for anyone who plays the Pennsylvania 30/5 The perfect array with 15 groups, of course to be short (15 chances in 100%) will repeat often, these groups = 0000 and 2222 very hard to leave The fifth random number can be 17-30, you have good guaranteed 100% with the first block 15 groups ok, sometimes repeated 3-4 digits of a result for other The digit from the front, so the hardest part are the endings or final digit ranging from 0 to 9, you can use a pick 4 as if it were, of course... [ More ]

Reply #45

dr san — Sun, 10 Jun 2012 16:28:40 GMT

Hello, rl and winsu the lindalau with patience and a little solf will understand, I took Also to see est pattern without solft, will be very difficult to understand, especially The analysis of the vertical position, it is difficult to catch up after all the policies is easy, as is appearing patterns, needs little solft.

Reply #44

Lindalu711 — Sun, 10 Jun 2012 16:13:25 GMT

Good Morning RL,

I have been reading this stuff for 4 days, maybe I am not as mathematically advanced as some of you here on the LP, or maybe because many words will not translate from Portuguese to English, in any case I am really lost. Could you please help explain it to me? Maybe if I saw an example, from the start to a finished set of numbers I might grasp it a bit better.

Here s what I understand so far if correct:

Example;

02 03 06 28 33

0 0 0 2

2 3 6 8

Throw out

Reply #43

dr san — Sun, 10 Jun 2012 15:44:28 GMT

0 0 0 2 formations of all four pairs have also all the odd = eg 1113 3359 etc.

0 0 0 4

0 0 0 6

0 0 0 8

0 0 2 0

0 0 2 2

0 0 2 4

0 0 2 6

0 0 2 8

0 0 4 0

0 0 4 2

0 0 4 4

0 0 4 6

0 0 4 8

0 0 6 0

0 0 6 2

0 0 6 4

0 0 6 6

0 0 6 8

0 0 8 0

0 0 8 2

0 0 8 4

0 0 8 6

0 0 8 8

0 2 0 0

0 2 0 2

0 2 0 4

0 2 0 6

0 2 0 8

0 2 2 0

0 2 2 2

0 2 2 4

0 2 2 6

0 2 2 8

0 2 4 0

0 2 4 2

0 2 4 4

0 2 4 6

0 2 4 8

Reply #42

dr san — Sun, 10 Jun 2012 15:29:44 GMT

Hello nail top, you must go in search of patterns, look at the example Result = 08 09 23 24 32 Next results = 15 23 29 32 38 Of the first four digits repeated 3.9'm talking about the final digit 0-9 So of the 10 000 possible solft, filtraria groups that have the 3.9 digit Of course it could be 8.4, which make mass repeats, endings exatemente With a pick4,

Reply #41

dr san — Sun, 10 Jun 2012 14:50:54 GMT

Hello nail top, of course, the great difficulty is to hit the the ending, you can use the pick4 pick3 or when it is for couples, is a game to play with friends, make a bowling The final digit can be any pair example 0-9 2,4,6,8. 1,5,7,9 or odd, Then you can use the sitema rl randonlogic to filter the final digits, has several Statistics in the vertical, if it were easy we would have cracked the lottery, you need solft To simulate conditions, filter the results above, with pen to paper is not pos... [ More ]

Reply #40

topnail — Sun, 10 Jun 2012 13:32:16 GMT

it is not work for me

i agree is 100 % that all first digit of the set

but how many combianation will be fill in second digit thai is ?

too much to lose

sorry

Reply #39

dr san — Sun, 10 Jun 2012 13:06:02 GMT

Hello, xaab the rl understood, perfect xaab the fifth number, can also be the 1st or 2nd in the 3rd or fourth position, the above examples are the fifth position of the random number, But it could be the other four posi oe Xaav the list of 37 is 100% in all drawings, but you do not need to play all 37 You can make the analysis of the three frequencies, hot, medium, and cold, eg The training = 000 332 333, are very hard to leave. Can also choose So even or only odd = odd pairs = 0022 or 1133 or v... [ More ]

Reply #38

RL-RANDOMLOGIC — Sun, 10 Jun 2012 12:41:13 GMT

xaab

dr san is using 4 decade digits for four of the numbers then allowing the fifth to be picked randomly.

The list is the combinations of decades. 3 3 3 3 = 4 numbers in the 30's + one randomly generated

set. You have to select one decade group from the list and if correct then you have at least one 4of5

and many 3of5's that could also be 4of5 if the random number also matches a number in the set. It

would only work if you can pick the correct one from the list. If you play them... [ More ]

Reply #37

dr san — Fri, 08 Jun 2012 17:37:15 GMT

Hello sergem, but the difficulty will always be 0-9 up because I fear 10 000 combinations It's like a pick four dismembered, the system is done in two parts The first part is 100% guaranteed at least one of the 37 combinations hits forever!, But you can do with only three have 20 combinations, and unite the extreme pairing and three in the center, to predict the 0-9 can be make it into a pick3 There are several way to do this is important is the matrix perfect 100% in all drawings, Having secure... [ More ]

Reply #36

SergeM — Fri, 08 Jun 2012 17:09:53 GMT

Ol , x1kosmic, ok perfeito, Dr. sistem san, foi dividido em duas partes ok na frente de d gitos que varia de 3 0 e finais variando de 0 a 9, o quinto n mero selvagem (aleat rio, voc pode escolher na 5 posi o no as estat sticas de vis o vertical para ver as tr s frequ ncias, xkosmic, o n mero de curingas tamb m pode ser um 0023 x = x o curinga) pode ser o terceiro segundo e quarto e quinto do exemplo 4 {1,2,3 x3. Assim voc pode jogar o joker com 5 possobidades abaixo dos 5 posi es, outra possibil... [ More ]

Reply #35

SergeM — Fri, 08 Jun 2012 17:07:14 GMT

@ san

It helps to reverse the string to make yourself less comprehensive!

uoy knaht ?9/93 yrettol a ni ti ees nac usniw ,93,83,62 62 eb ll'tI neht ,9,8,7,6 = gnitaeper-non eb tsum slanimret eht esac siht ni oS rebmun eht taeper lliw oa naimret eht taeper ot tnorf 3,3,2,2 = tigid elpmas ton naC tigid lanif ro sgnidne detaeper era tnorf fo spuorg nehw rO nac ,63 62 61 60 semoceb ti neht ,6666 sepyT detaeper eb nac sgnidne = 3,2,1,0 = elpmas taeper oN si stigid fo spuorg tnorf eht nehw ti ee... [ More ]

Reply #34

dr san — Fri, 08 Jun 2012 13:21:00 GMT

Helo x1kosmic has to do in four editions, because whenever a group has zero or a number

And another two or more numbers in a group 100% will always carry

01 02 03 04 05 06

07 08 09 10 11 12

13 14 15 16 17 18

19 20 21 22 23 24

25 26 27 28 29 30

31 32 33 34 35

result=07 16 20 21 35

Reply #33

dr san — Thu, 07 Jun 2012 21:31:10 GMT

Hello, 1kosmic, I did limit the pairs 01-08 and 30-35 gave 48 pairs. Following pairs ok, you can see the use of these 48 pairs? well after It is being put the pair,

01 30

01 31

01 32

01 33

01 34

01 35

02 30

02 31

02 32

02 33

02 34

02 35

03 30

03 31

03 32

03 33

03 34

03 35

04 30

04 31

04 32

04 33

04 34

04 35

05 30

05 31

05 32

05 33

05 34

05 35

06 30

06 31

06 32

06 33

06 34

06 35

07 30

Reply #32

x1kosmic — Thu, 07 Jun 2012 21:12:28 GMT

Yes,, and as my lottery only goes to 35

it's better than 39

and of course, sometimes there's not a 30 number at all.

will try and back-test for the front part.

Reply #31

dr san — Thu, 07 Jun 2012 21:01:14 GMT

Hello, x1kosmic, pays attention, the system dr san, has many ways = Look at the example of the draw = 07 = 16 20 21 35 Let's make the limit 01 to 10 to 1 or smaller number of the pair and the limit of 21-39 for the 5th or the greatest number = total pairs this limit = 01 to 10 and 21 39 = are 90 pairs within the 90 pairs, can see for three frequencies, or look there is no repetition of the digits 07 35, ok! 07 35 the pair, the other three numbers ranging within the limits 07-35 will 08-34 07 XXX... [ More ]

Reply #30

dr san — Thu, 07 Jun 2012 20:10:53 GMT

Hello, x1kosmic, ok perfect, Dr. sistem san, was divided into two parts ok in front of digits ranging from 3 0th and endings ranging from 0 to 9, the fifth number is wild (random, you can choose in the 5th position in the vertical view statistics to see the three frequencies, xkosmic, the number of wildcards can also be a 0023 x = x is the wildcard) It may be the 2nd 3rd and 4th and 5th of the 4th example {1,2,3 x3. So you can play the joker with 5 possobidades below the 5 positions, Another pos... [ More ]

Reply #29

x1kosmic — Thu, 07 Jun 2012 19:51:32 GMT

I get it Dr. San

My last states results were 07- 16- 20- 21- 35

the formula, or set-up, should have been

0- 1- 2- 2 but don't do the last number

Dr. San ? if thats it I like

Reply #28

dr san — Thu, 07 Jun 2012 19:31:46 GMT

hello 562soldier, You can do so in the system dr san You can see the ends of the pairs 01 to 15 and 25 to 39 = 210 pairs have al Giving the 1st position on the edge 01-15 and 5th position in the limit of 25 A39 = 210 pairs Example of pair 05 = 32 then instead of four can use three, the matrix is perfect combinations of 20 2 = 000, 001 up to 20 combinations, so you chose the example a562soldier 05.32 the pair the other three numbers can only be 06 to 31 within limits means 05 xxx 32, there goes t... [ More ]

Reply #27

topnail — Wed, 06 Jun 2012 14:05:16 GMT

Dr san

thank you so much for thr hard work

Reply #26

dr san — Wed, 06 Jun 2012 11:54:04 GMT

Hello, top, you have patience that I do not play now, you simulate some situations, ok I said that the fifth paragraph, must be in fifth position. But it can be One of the five positions = 1,2,3,4 1,2,3,5 1,2,4,5 1,3,4,5 2,3,4,5 1,2,3,4 x 1,2,3, x5 1.2, x 1 x 3.5, x 2,3,4,5 3,4,5 0 0 0 1 0 0 1 0x 2 2 33 222x3 So where is the (x) is the fifth number, can be played in 5th position, but also in other four positions, will clear more cards, to give examples (simulate) we will need solft To see the th... [ More ]

Reply #25

topnail — Wed, 06 Jun 2012 05:03:48 GMT

can you make some set number from 1-31 test

see how we do ,the drawing is wed 06/06

Reply #24

topnail — Wed, 06 Jun 2012 04:58:46 GMT

my state game only 31 number

so the digit 3 only have 2,30-31

i see the 0,0,1,2,2

0,1,1,2,2,

are draw more often

Reply #23

dr san — Wed, 06 Jun 2012 04:50:54 GMT

Hello, top, only four 0,1,2,3 0,2,3,3 top There are 4 digits in front of your example I have seen more You have to create a rotating system, to take a quadrant, as not to be ssabe which has 4 options, you know, you have to leave an industry outside, you can go wrong

Reply #22

dr san — Wed, 06 Jun 2012 04:46:08 GMT

hello, look at this official result = 07 08 11 14 27 It was off the 3rd quadrant (blue) then groups that have the blue quadrant nine numbers You can not play, or the 5th number, it is obvious why it did not, so must be the whole number to delete, only the ending is just,

Reply #21

topnail — Wed, 06 Jun 2012 04:43:24 GMT

dr san

this is what i m going to do

0_ 0_ 1_ 2_2_

0_1_1_2_2_

0_1_2_2_3_

i use the first and the last is my key

and fill in those 2nd 3th 4th position

Reply #20

dr san — Wed, 06 Jun 2012 04:29:29 GMT

Hello, note that the number 33 is the fifth number ok, if there is a standard 100% that a group has zero or one number and one has two billion or more in a lottery and sweepstakes 39/5 Let's please not know which, of course, so do the four options, taking hours, the quadrant One, or both to 0,1,2,2 and 5 termian oes number, then a card without the 1st quadrant, then with one out 2nd quadrant, both digits as numbers, then the 3rd and 4th quandrantes, take care to number 5 , making 4 options one w... [ More ]

Reply #19

dr san — Wed, 06 Jun 2012 04:20:24 GMT

Matriz do 39/5

01 02 03 04 05 06

07 08 09 10 11 12

13 14 15 16 17 18

19 20 21 22 23 24

25 26 27 28 29 30

31 32 33 34 35 36

37 38 39

Result=02,15,26,30,33

Reply #18

dr san — Wed, 06 Jun 2012 04:13:15 GMT

Hello top, can not forget this pattern ok, split into four gupos a lottery 39/5 group has a zero or a number, and another, you have two or more This pattern is 100% and make the ideal option 4, taking out a cda uindades and termain oes of each quadrant, and did not play the fifth number of the quadrant, because not even the Understand, this pattern is 100% and well-being tends

Reply #17

topnail — Wed, 06 Jun 2012 03:50:39 GMT

dr san

in my state game

i have to hit 5 number to win 5000

any thing low than 5 are not much

the jp i have to hit 5 plus the wildcard

there is 16 wildcard to be draw in 1

thanks for your input

Reply #16

dr san — Wed, 06 Jun 2012 01:45:29 GMT

Hello top, this system is good for sweepstakes, or play in groups The repetition of a result to another, you can help, note the number Bonds and the fifth number is ok and then the endings we have 10 000 poss ves The great advantages that your drawing within the next 37 groups with some of the training It is there, if you 15 groups insides of a 37, can be used as fixed, but the big problem is the ten thousand termian oes, and the fifth number, well it would be easy, but half The number to play t... [ More ]

Reply #15

topnail — Wed, 06 Jun 2012 01:34:17 GMT

dr san

the second part is hard

there is alot of combination to fill in

i will try this in my state wildcard 2 game

they are 31 number and 16 bonus wildcard

i have to hit 5 number and the wildcard to take the JP HOME

Thank s

Reply #14

dr san — Wed, 06 Jun 2012 01:34:03 GMT

Hello, ok top, but where has the perfect dash goes to termenia ao Sometimes endings repeat a lot to another, and also the digit from the front Ok perfect top 0 1 1 2 Top, you saw that when you define for a repeated them, the ends can not Be repeated, such endings chosen = 1, 6,6,7, can not have two 6 Why going to give = 01 16 16 27, then the endings (those that van completing Tends to be different in the top position going to look now 6,6,1,7 = 06 16 11 27, can now Where is the dash in your exam... [ More ]

Reply #13

dr san — Wed, 06 Jun 2012 01:07:34 GMT

Hello xaab with patience you will discover, and then two seconds, will be able to understand everything, perhaps a planilia the draw 39/5 with separate digits may be worth a thousand words, ok, what part do you not understand

Reply #12

topnail — Wed, 06 Jun 2012 01:07:27 GMT

so,on the first 4

0_ 1_ 1_ 2_

or

0_ 0_ 1_ 2_

or

0_ 1_ 1_ 2_

or

0_ 1_ 2_ 2_

and fill in the last digit of those set above

is that right

Reply #11

xaab — Wed, 06 Jun 2012 01:00:43 GMT

I wish I can understand what you're talking about. Only then I might be able to remember you. Maybe you can try translate to German or French first and then translate that to English. Try that to see if it's any better.

Reply #10

dr san — Wed, 06 Jun 2012 00:59:21 GMT

Hello, I need more experienced members with wuinsu, to see so When you repeat a number or digit in the column, if the forecast or filter I need winsu to see it when the front groups of digits is No repeat sample = 0,1,2,3 = endings can be repeated Types 6666, then it becomes 06 16 26 36, can Or when groups of front are repeated endings or final digit Can not sample digit = 2,2,3,3 front to repeat the termian ao will repeat the number So in this case the terminals must be non-repeating = 6,7,8,9,... [ More ]

Reply #9

dr san — Tue, 05 Jun 2012 23:48:44 GMT

Hello, if your lottery is 39/5 ok!

First step, get all the sweepstakes ok

And separating the digit from the front and finishing

12 15 23 25 36

Top, o5 (fifth number does not enter 0 in the case study 36) the last position

Only be released later as a random number up because 25 to 39,

Top 4 I did to set up because first you have to hit 4 numbers

So the 1st part is guaranteed to hit 100% in 37 groups, these 37 hits

Attention is maetado the process, you can further reduce th... [ More ]

Reply #8

topnail — Tue, 05 Jun 2012 23:24:38 GMT

dr san

it still very hard for me to understand

please tell me more

thanks

Reply #7

dr san — Tue, 05 Jun 2012 23:11:44 GMT

Hello, to 562, are you with the results in order of draw To operate at 100% until the fourth number 0, you have to put the results In ascending order! INCREASING ORDER, AND SPLIT TYPE 1 EXAMPLE = DRAW ORDER 14 25 16 17 37 ascending 14,16,17,25 = 37 digit = front 1,1,1,2 = 37 in this 100% 562, the fifth number does not enter the study, in this case 37 is put up because it will random 25-39 The ends of the sample = 4,6,7,5. , Which can be feiro like uam pick4 or vertical view, having groups of fre... [ More ]

Reply #6

a562soldier — Tue, 05 Jun 2012 22:35:43 GMT

Can someone please explain to me what is going on with the above formula? I don't get it. Im lost as to what we need to do.

Last 5 drawings for CA Fantasy 5 were..

14-25-16-17-37

33-9-3-12-39

5-16-30-18-15

3-21-4-36-26

7-23-37-15-24

An example would really be appreciated guys. Thank you.

Reply #5

lakerben — Tue, 05 Jun 2012 20:55:53 GMT

Good job! Bueno

Reply #4

dr san — Tue, 05 Jun 2012 20:55:46 GMT

Hello, if someone in the forum, you can build a planilia excel, with the matrix, you can! It has to do so, take all the draws of 39/5, separate the digits from the front example 02 03 12 15 27 = 0 2 0 3 1 2 1 5 2 7 Use the first 4 digits = 0,0,1,1 the 5th number does not enter the study After separating a list, see the three frequencies ok (gealmentes the hot is better) The second part, that the endings = 2,3,2,5, If you can see how pick4 or analyze the vertical position of each of the four firs... [ More ]

Reply #3

dr san — Tue, 05 Jun 2012 20:37:47 GMT

Hello, I did not say that it is easy, but the array is 100% ok, this list of 37 groups you can reduce even more, making grpos of three frequencies of hot and cold media, and also delete Formations all such pairs = 0000 2222 1111 3333 or all odd, almost can exclude, generally mixed dao, even and odd, repeating, is the front of the number!! The digital termina oe or 0-9, you can ESAF by statistical vertically from each of the four positions, well then we still have to hit the 5 numbers that usuall... [ More ]

Reply #2

dr san — Tue, 05 Jun 2012 20:21:35 GMT

Hello, xaab, attention is the front of the numbers ok, you can do so Take the results of 39/5 separate digits of the front example = 02 03 06 21 35 = the front digits = 0,0,0,2,3 For the study are the first 4 are = 0,0,0,2, the third digit is part of the 5th position Xaab, did not speak up because it is easy to hit the endings that are 10 000 (or a pck4) Then set the number of 5 th position, just gave this matrix by it is 100% of what promises Of course missing endings and ultimom, would do much... [ More ]

Reply #1

xaab — Tue, 05 Jun 2012 20:03:54 GMT

She should be very rich since she hits 4of5 100% everytime.

lottery 39/5

dr san — Tue, 05 Jun 2012 19:44:38 GMT

Hello, this is for anyone who plays a lottery 39/5, has been optimized, it removed the bugg!

She is perfect, it is only here on the forum! Gift of Dr. san, she always hits four numbers in 100% of the draws of 39/5, but attention is the front part of the numbers

Example =

08 12 23 32 36 = she hits the first four digits = 0,1,2,3

The random number will be the fifth, the fifth position is ok

The perfect matrix consists of 37 lines, or combinations

Of course after the second part,