Some boring statistical mathematics meets MM numbers https://www.lotterypost.com/thread/269642 Lottery Post Forum Topic: Some boring statistical mathematics meets MM numbers en-us Lottery Post RSS Generator Reply #10 https://www.lotterypost.com/thread/269642/3404656 https://www.lotterypost.com/thread/269642/3404656 Thu, 26 Dec 2013 00:50:23 GMT SergeM Forget the beer and cigarettes, go to the gym, dojo or see some sifu.

]]> SergeM Reply #9 https://www.lotterypost.com/thread/269642/3403881 https://www.lotterypost.com/thread/269642/3403881 Wed, 25 Dec 2013 13:14:33 GMT LottoBoner I forgot to play tuesday.

Good thing. I saved myself some money that I can now spend on something better.

Like beer or cigarettes.

]]> LottoBoner Reply #8 https://www.lotterypost.com/thread/269642/3403823 https://www.lotterypost.com/thread/269642/3403823 Wed, 25 Dec 2013 11:56:35 GMT SergeM Tue, Dec 24, 2013 23-34-53-58-73, Mega Ball: 02

]]> SergeM Reply #7 https://www.lotterypost.com/thread/269642/3395027 https://www.lotterypost.com/thread/269642/3395027 Wed, 18 Dec 2013 19:59:54 GMT SergeM That would be a FullLotto().

Three random versions for the numbers, you can add your mega balls:

50 72 10 29 37 + 68 13 62 49 17 + 4 69 51 5 2 + 16 67 34 22 57 + 65 20 27 66 32 +

45 15 71 25 46 + 56 54 14 19 74 + 21 58 30 12 43 + 35 18 64 7 55 + 38 63 6 44 39 +

60 33 11 52 75 + 8 47 9 24 48 + 42 61 59 28 40 + 36 73 23 70 3 + 31 53 1 41 26

19 33 25 49 64 + 35 34 47 51 75 + 3 42 5 46 13 + 38 45 57 22 68 + 65 39 16 67 37 +

74 73 52 14 50 + 4 66 36 9 8 + 28 44 1 30 43

]]> SergeM Reply #6 https://www.lotterypost.com/thread/269642/3395019 https://www.lotterypost.com/thread/269642/3395019 Wed, 18 Dec 2013 19:52:32 GMT RJOh I prefer playing all 75 white ball numbers and all 15 mega ball numbers in 15 lines for $15, that way I'm guaranteed at least a $1 win or better when ever I play.

]]> RJOh Reply #5 https://www.lotterypost.com/thread/269642/3395010 https://www.lotterypost.com/thread/269642/3395010 Wed, 18 Dec 2013 19:43:56 GMT SergeM If you want to bulk it with one mega ball and one number, you find the necessary budget in the table.

So for example playing 29 as lowest ball number with mega ball 1, would cost you 163,185 dollars.

]]> SergeM Reply #4 https://www.lotterypost.com/thread/269642/3391205 https://www.lotterypost.com/thread/269642/3391205 Mon, 16 Dec 2013 15:59:07 GMT SergeM Compare and see for yourself.

Datum N1 N2 N3 N4 N5 MB

22/10/2013 2 3 19 52 71 14

25/10/2013 6 16 45 54 60 15

29/10/2013 20 33 50 53 54 7

1/11/2013 32 35 49 62 67 1

5/11/2013 2 11 42 64 74 2

8/11/2013 41 42 51 57 65 7

12/11/2013 20 30 32 42 71 15

15/11/2013 25 44 49 54 63 8

19/11/2013 14 15 29 49 63 2

22/11/2013 17 23 35 36 44 8

26/11/2013 27 44 59 74 75 3

29/11/2013 9 41 43 47 57 5

3/12/2013 7 12 41 44 59 3

6/12/2013 11 29... [ More ]

]]> SergeM Reply #3 https://www.lotterypost.com/thread/269642/3391201 https://www.lotterypost.com/thread/269642/3391201 Mon, 16 Dec 2013 15:51:10 GMT SergeM Sure, you can. You also can wheel all numbers with a program, rentware, freeware or payware. You also have to get organised like S. Mandel and other bulk players. You can't do it alone. So, I play 1 to 20 combinations and it stops there!

If you buy all combinations but one, the last one that you didn't play, may be the winning ticket. - Me

]]> SergeM Reply #2 https://www.lotterypost.com/thread/269642/3389358 https://www.lotterypost.com/thread/269642/3389358 Sun, 15 Dec 2013 12:21:18 GMT dr san Hello serge can create wheels watching the numbers at each position in its largest Harnessing example if 0 23 has higher output in 2nd position filter wheel for the best

Index, or unfold the wheel has observed the best index.

]]> dr san Reply #1 https://www.lotterypost.com/thread/269642/3386707 https://www.lotterypost.com/thread/269642/3386707 Fri, 13 Dec 2013 19:17:28 GMT LottoBoner I might print this out when I get a chance.

I guess 23 is good as position two.

]]> LottoBoner Some boring statistical mathematics meets MM numbers https://www.lotterypost.com/thread/269642 https://www.lotterypost.com/thread/269642 Thu, 12 Dec 2013 19:10:39 GMT SergeM Sorting every combination high to low, we get a positional probability.

The counts:

number\position 1 2 3 4 5

1 1150626 - - - -

2 1088430 62196 - - -

3 1028790 119280 2556 - -

4 971635 171465 7455 71 -

5 916895 218960 14490 280 1

6 864501 261970 23460 690 5

7 814385 300696 34170 1360 15

8 766480 335335 46431 2345 35

9 720720 366080 60060 3696 70

10 677040 393120 74880 5460 126

11 635376 416640 90720 7680 210

12 595665 436821 1074... [ More ]

]]> SergeM