I need a Little Math Help - vtracs

Reply #15

mjoyg1123 — Tue, 25 Mar 2014 21:50:37 GMT

ineedahit:

Those are very good questions (and answers:) about vtracs!

We must never forget them. They are a serious curveball effect for the win!

mjoy

Reply #14

MonEl — Sun, 23 Mar 2014 19:23:01 GMT

You can of course play each of the 48 boxed combinations straight instead of boxed, but then you will spend $48 at $1 each or $24 at 50 cents each, instead of the $8 or $4, otherwise.

Reply #13

MonEl — Sat, 22 Mar 2014 12:21:16 GMT

Thanks

Reply #12

MonEl — Sat, 22 Mar 2014 12:19:55 GMT

Now there are 8 different single combos in a single vtrac number ... so 8x6 is 48 total Boxed possiblities

But that is only right if you play the 8 combinations BOXED.

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If you play the 8 combinations of a VTrac straight, then there are only 8 possibilities out of 1 thousand or 0.8%.

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If You play the 8 straight combinations of a VTrac BOXED, then you will have 48 BOXED possibilities out of 1 thousand or 4.8%.

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Good Luck

Reply #11

ineedahit — Sat, 22 Mar 2014 04:26:41 GMT

awesome Thank you MoneI .... im actually only looking for the average any single vtrac combo should hit boxed so that works .... so thats what i needed ... the reason i was saying straight is because i used how many times each number in the vtrac can hit straight and it was 48 ...but i see how i worded it wrong, but it got me to the right answer i guess in the end... thank you for responding... here is what i have been doing... i actually have a thread posting this test im doing..... i took 9 st... [ More ]

Reply #10

MonEl — Sat, 22 Mar 2014 03:24:51 GMT

I just now had enough time to take a good look at your post, sorry.

You posted:

Now there are 8 different single combos in a single vtrac number ... so 8x6 is 48 total straight possiblities

Wrong!!!

You should have posted this:

Now there are 8 different single combos in a single vtrac number ... so 8x6 is 48 total Boxed possiblities

That is now right!!!

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So that vtrac hitting has a 48 out of 1000 BOXED odds of hitting

Reply #9

ineedahit — Fri, 21 Mar 2014 06:07:32 GMT

thanks guys - i appreciate the responses ...im kind of surprised this isnt common knowledge to someone around here .. ive been tracking the due vtrac pairs and combos and the ones due do not take too long at all to hit .... i would like to have some averages to look at though , so i can see how many draws a due vtrac combo is over its average .... i started a thread yesterday using 9 states and their most overdue vtrac combos and there were 2 hits today..... ill see how it goes , im expecting mo... [ More ]

Reply #8

LAVERNE MALONEY — Thu, 20 Mar 2014 22:29:27 GMT

Hello there ineedahit, the best way in which to find out how many times a Vtrac will hit in your state is to count how many times the Vtrac has come out in a six month timespan then divide by six. The answer is the average amount of times that Vtrac will hit in your state. If you would then like to narrow the timespan you can do that as well.

In the Vtracs search engine load the Vtrac, set the parameters, when you get the results save it to your favorites, that way you can click on what you h... [ More ]

Reply #7

winsumloosesum — Thu, 20 Mar 2014 16:26:31 GMT

Posted this a couple months ago:

https://www.lotterypost.com/thread/267607

Use the files from the following download folder if your interested in using Excel:

Follow th instructions in the thread above for setting up your folders.

https://app.box.com/s/sqtqcetfb05va8pmj04d

Reply #6

winsumloosesum — Thu, 20 Mar 2014 16:15:17 GMT

VTRAC 101

We are reducing 10 digits down to 5.

Here's how:

Digits 0 5 = VTRAC 1

Digits 1 6 = VTRAC 2

Digits 2 7 = VTRAC 3

Digits 3 8 = VTRAC 4

Digits 4 9 = VTRAC 5

Some folks call them VTRAC's others may call them mirror digits.

1. Look for VTRAC's that have NOT hit in last 5 or more drawings. For example, if a VTRAC 1 (Digits 0 5) has not hit in the last 5 or more draws you would want to include both the digits 0 5

2. Decide what strategy to play. Play just double... [ More ]

Reply #5

Igamble — Thu, 20 Mar 2014 15:36:13 GMT

the only good way to make some advancment with vtrac is to keep trac of the missing vtrac pair .there is only a few of them andwhen one is missing more then 5draws ,then is time to act.but there is a better way to get ahead in p3 , by tracking the pair that is due like you were doing a while ago

Reply #4

Wentworth — Thu, 20 Mar 2014 14:07:01 GMT

what does that mean???????? are you maybe refering to this vtracs 1o1 course person? again if so its hard to understand what shes teaching... TNT????????

i just dont get vtracs! TNT

Reply #3

CARBOB — Thu, 20 Mar 2014 14:02:30 GMT

Search for TNT

Reply #2

Wentworth — Thu, 20 Mar 2014 12:39:41 GMT

I dont understand vtracs at all! So youre not alone! Ive asked about them on here but the replies just make it more confusing! They talk legalize only with Lotto

language only they understand!!! Can anyone tell us about v tracs in Laymans language

Reply #1

MonEl — Thu, 20 Mar 2014 12:20:36 GMT

There are 1000 pick 3 Straights

There are 125 Straight VTracs

Each VTrac equals 8 Straights

There are 60 Singles VTracs such as 123

There are 60 Doubles VTracs such as 112

There are 5 Triples VTracs such as 444

60 + 60 + 5 = 125 Straights VTracs and each of them equals 8 pick 3 Straights

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A Straight pick 3 is expected to hit 1 time each 1000 drawings or 0.1% of the time

A Straight VTrac is expected to hit 8 times each 1000 drawings or 0.8% of the ti... [ More ]

I need a Little Math Help - vtracs

ineedahit — Thu, 20 Mar 2014 04:00:25 GMT

Allright , im hoping someone knows this info, or can easily figure it out, since there are so many people here on this part of the forum who are math wiz's... or there may even be a few people around here who know this off the top of their head...

How many drawings is a vtrac combo expected on average to hit ( triple - single - double)

so the answers im looking for is what goes in the questino marks..

v123 is expected on average to hit once every ???? drawings

v112 is expected on ave... [ More ]