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		<title>Reduce the Pick 3 Odds To 3.5:1</title>
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			<title>Reply #13</title>
			<link>https://www.lotterypost.com/thread/274172/3559678</link>
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			<pubDate>Wed, 09 Apr 2014 11:12:05 GMT</pubDate>
			<dc:creator>MonEl</dc:creator>
			<description><![CDATA[<p>As you know, doubles are 3 ways numbers and singles are 6 ways numbers.</p>]]></description>
			<category>MonEl</category>
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			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/274172/3559673</link>
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			<pubDate>Wed, 09 Apr 2014 11:09:25 GMT</pubDate>
			<dc:creator>MonEl</dc:creator>
			<description><![CDATA[<p>Jimmy<br /><br />I understand now, I thought that you was talking about pairs repeating on the very next draw.<br /><br />-----------------<br /><br />On 1 draw there are 3 pairs, so 3 X 5 = 15 pairs for 50% wins in the very long run of maybe 1000 draws.<br /><br />-------------------<br /><br />8 pick 3 numbers have 24 pairs or fewer.<br /><br />So, 24 pairs and if no doubles fall maybe about from 80% to 100% chance (I don&#x27;t remember for sure) of one of those pairs falling on the very next single draw.<br /><br />Those are the 8 pick 3 numbers that... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/274172/3559673">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>MonEl</category>
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			<title>Reply #11</title>
			<link>https://www.lotterypost.com/thread/274172/3559568</link>
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			<pubDate>Wed, 09 Apr 2014 08:05:05 GMT</pubDate>
			<dc:creator>jackpotismine</dc:creator>
			<description><![CDATA[<p>A long time ago I had posted a strategy like the OP. The difference was that when you get a double- digit number, you make pairs out the the draw before the double-digt. Usually the pairs fall within 5-6 draws. Here&#x27;s what I mean.<br /><br />Let&#x27;s say:<br /><br />225 falls and the draw before the double was<br /><br />468 then you will use the 46,48,68 as your pair to play for the next 5-6 draws. Another thing to add is that when the pair does come out, it usually doesn&#x27;t fall in the same order. In order words if the 4... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/274172/3559568">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>jackpotismine</category>
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			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/274172/3559545</link>
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			<pubDate>Wed, 09 Apr 2014 06:07:38 GMT</pubDate>
			<dc:creator>jimjwright</dc:creator>
			<description><![CDATA[<p>Not sure why you are addressing me I made no statement about pairs repeating in the next draw. All I said is if you use a representative sample of say 1000 draws then the median value for a pair to repeat is 5 draws.<br /><br />Jimmy</p>]]></description>
			<category>jimjwright</category>
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			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/274172/3559513</link>
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			<pubDate>Wed, 09 Apr 2014 05:08:07 GMT</pubDate>
			<dc:creator>MonEl</dc:creator>
			<description><![CDATA[<p>Beware, first check the game that you are thinking about playing, I just took a look at one game and on 40 past draws there were only 3 pairs repeats. study your game, some patterns might be more dependable than others.</p>]]></description>
			<category>MonEl</category>
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			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/274172/3558922</link>
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			<pubDate>Tue, 08 Apr 2014 21:34:55 GMT</pubDate>
			<dc:creator>BobP</dc:creator>
			<description><![CDATA[<p>I believe the occurence of filter settings is dependent on their percentage within the population.<br /><br />I do believe any box number drawn has a 50/50 chance of repeating within 15 draws.<br /><br />BobP</p>]]></description>
			<category>BobP</category>
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			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/274172/3558339</link>
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			<pubDate>Tue, 08 Apr 2014 16:35:59 GMT</pubDate>
			<dc:creator>CARBOB</dc:creator>
			<description><![CDATA[<p>JJ,<br /><br />I recall reading and I think it was in a post by Thoth. That any filter, has a 50/50 chance of repeating witin 5 draws. I&#x27;m trying to find the post.</p>]]></description>
			<category>CARBOB</category>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/274172/3558177</link>
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			<pubDate>Tue, 08 Apr 2014 14:32:00 GMT</pubDate>
			<dc:creator>jimjwright</dc:creator>
			<description><![CDATA[<p>You can intrepret the stats anyway you want, the median value for any pair repeating is 5 draws. This means 50% of the time a pair in 5 draws will repeat and 50% of the time it will be 6 draws or further out.<br /><br />Jimmy</p>]]></description>
			<category>jimjwright</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/274172/3557880</link>
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			<pubDate>Tue, 08 Apr 2014 05:14:59 GMT</pubDate>
			<dc:creator>MonEl</dc:creator>
			<description><![CDATA[<p>So nothing is for sure, a pair might repeat any time within 1 to 10 draws or even a few more.<br /><br />One would need a way or ways to get closer to the When .<br /><br />-----------------------------------<br /><br />There are 3 digits on singles and 3 pairs, that would leave:<br /><br />10-3=7 digits not accounted for, so:<br /><br />For each pair 7 X 3 pairs = 21 combinations per draw.<br /><br />One would need a way of reducing those 7 digits to some fewer, that is of getting closer to the one next winning digit.<br /><br />-----------<br /><br />Next,... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/274172/3557880">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>MonEl</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/274172/3555479</link>
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			<pubDate>Sun, 06 Apr 2014 17:16:48 GMT</pubDate>
			<dc:creator>jimjwright</dc:creator>
			<description><![CDATA[<p>Well since depending on the long sum it will vary from draw to draw, its probably safe to say that it will eliminate approximately 160 straight combinations.<br /><br />If your playing locally at a retail store then you still have to come up with additional filters. For the online player with $900 payout your on you way to having a playable strategy since you are already in the profit zone. You just need a couple more filters that hit with a 90% consistency.<br /><br />I mainly focus on eliminating rootsum/shor... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/274172/3555479">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>jimjwright</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/274172/3555371</link>
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			<pubDate>Sun, 06 Apr 2014 16:19:04 GMT</pubDate>
			<dc:creator>debron</dc:creator>
			<description><![CDATA[<p>Thanks Jimmy. Playing the no sum repeat strategy, how many sets does that leave to play</p>]]></description>
			<category>debron</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/274172/3551945</link>
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			<pubDate>Fri, 04 Apr 2014 03:19:31 GMT</pubDate>
			<dc:creator>jimjwright</dc:creator>
			<description><![CDATA[<p>In general for any state pick 3 game the median value for any pair to repeat is 5 draws. The mean value is between 7-8 draws.<br /><br />Here is the current chart for California for the last 400 draws.<br /><br />anypair<br /><br />The thing that stands out from this chart is the Sums Repeat column. This column counts how often the sums, shortsum, and root sum repeated from the previous draw. If they all repeated you would have a value of 3. If none repeated then the value is 0. So the odds play is to play for the sum,... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/274172/3551945">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>jimjwright</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/274172/3551570</link>
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			<pubDate>Thu, 03 Apr 2014 22:29:23 GMT</pubDate>
			<dc:creator>river26</dc:creator>
			<description><![CDATA[<p>not for me</p>]]></description>
			<category>river26</category>
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			<title>Reduce the Pick 3 Odds To 3.5:1</title>
			<link>https://www.lotterypost.com/thread/274172</link>
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			<pubDate>Thu, 03 Apr 2014 21:54:59 GMT</pubDate>
			<dc:creator>debron</dc:creator>
			<description><![CDATA[<p>Can you win the Pick 3 with reduced odds? Well, here&#x27;s one way to do it.<br /><br />Take the last pick and divide it into 3 pairs. 123 becomes 12,23,13 etc.<br /><br />You play those 3 picks for the next two consecutive games. You just need to pick the third number correctly.<br /><br />The pairs will be correct about 20% of the time in CA (check your state).<br /><br />Pick 3 box in CA pays $80, so your winning Expected Value is $16.<br /><br />Your cost per box play is 2 games x 3 picks or $6. Win $10 per game with 1... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/274172">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>debron</category>
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