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		<title>1&#xba; ching in lottery?</title>
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			<title>Reply #29</title>
			<link>https://www.lotterypost.com/thread/280103/3768796</link>
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			<pubDate>Sun, 07 Sep 2014 14:52:05 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello flossdog, you can use 5 or 6 previous draws And see for each code position 0.1, and see how it Relates to neighboring upright position, course it will have to play at least 5 bets</p>]]></description>
			<category>dr san</category>
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			<title>Reply #28</title>
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			<pubDate>Sun, 07 Sep 2014 14:42:30 GMT</pubDate>
			<dc:creator>flossdog</dc:creator>
			<description><![CDATA[<p>you can use them as pairs of the subset of the previous draw in a horizontal, vertical or diagonal manner. When following repeated pairs subsequently arrange themselves into a pair of digits that has appeared the most in x number of drawings, assimilate numbers that follow numbers and you will get a reduced set. I hit 3/5 in 5/39 using this with a few tickets. However one must know precisely the digits following . Much research is needed for your lotto</p>]]></description>
			<category>flossdog</category>
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			<title>Reply #27</title>
			<link>https://www.lotterypost.com/thread/280103/3768523</link>
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			<pubDate>Sun, 07 Sep 2014 05:44:35 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, you can use the last 5 sweepstakes to see<br /><br />Upright position by code<br /><br />example<br /><br />459<br /><br />863<br /><br />250<br /><br />159<br /><br />753<br /><br />1st column = 4,8,2,1,7 = CODIG = 1,1,1,0,0<br /><br />2nd = 5,6,5,5,3 1,1,1,1,0<br /><br />3rd column = 9,3,0,9,3 = 0,0,0,0,0<br /><br />1 1 0<br /><br />1 1 0<br /><br />1 1 0<br /><br />0 1 0<br /><br />0 0 0</p>]]></description>
			<category>dr san</category>
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			<title>Reply #26</title>
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			<pubDate>Sun, 07 Sep 2014 04:27:43 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, garyo another way to represent the binary<br /><br />2 = 1<br /><br />9 = 0<br /><br />4 = 1<br /><br />7 = 0<br /><br />5 = 1<br /><br />3 = 0<br /><br />6 = 1<br /><br />1 = 0<br /><br />8 = 1<br /><br />0 = 0 in Example 3 and pick 4 pick<br /><br />458 = 111. another ex = 290 = 100<br /><br />Pick 4 4591 = 1100</p>]]></description>
			<category>dr san</category>
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			<title>Reply #25</title>
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			<pubDate>Sun, 07 Sep 2014 01:08:16 GMT</pubDate>
			<dc:creator>PeerGynt</dc:creator>
			<description><![CDATA[<p>I&#x27;m starting to get the gist of what you&#x27;re getting at, Dr. San. It&#x27;ll take some more study and brain-bending to fully grasp it. It&#x27;s definitely intriguing. I think I see what you&#x27;re going at, trying to identify patterns of recurrence - sort of reminds me of what Adobea aims at.<br /><br />I&#x27;m still not entirely sure how this relates to the iChing, except as maybe an available model. I really don&#x27;t think the iChing has any secrets of mathematics to impart... but what do I know? That kind of play seems b... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/280103/3768238">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>PeerGynt</category>
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			<title>Reply #24</title>
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			<pubDate>Sat, 06 Sep 2014 21:01:30 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello, peer, when, can join the Cars table with 0 1 ching, we<br /><br />see trends in patterns of both the left and right, etc. acim low table<br /><br />values ??w = 1.0, of course we will have to play plays at least 5 games, for more in various raffles, peer, fancies you will be part of 50/50 when you can create the system</p>]]></description>
			<category>dr san</category>
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			<title>Reply #23</title>
			<link>https://www.lotterypost.com/thread/280103/3767872</link>
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			<pubDate>Sat, 06 Sep 2014 20:33:39 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, peer, let&#x27;s try to create a table of standards<br /><br />0- of 9 per column = wo1<br /><br />We where the 1st ching can join the chaotic table<br /><br />We will have to play at least five games because<br /><br />W01 The code parses per column vertically, ok<br /><br />Finding a pattern in the table both online<br /><br />or column<br /><br />Example = 01w1w = singfica = 5,8, .....<br /><br />In the 1st column ..<br /><br />It&#x27;s a system that we have yet to create and test. noted that<br /><br />the group center<br /><br />The 1st ching may inspire us in preventing... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/280103/3767872">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #22</title>
			<link>https://www.lotterypost.com/thread/280103/3767851</link>
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			<pubDate>Sat, 06 Sep 2014 20:14:02 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>A B C D E F<br /><br />A 1 w 0 w 0 1<br /><br />B w w 0 w 0 w<br /><br />C w w w 1 0 1<br /><br />D 1 w 0 0 w w<br /><br />E 1 w w 0 1 0<br /><br />F 1 1 w 1 w 0<br /><br />G w w w 1 w 0<br /><br />H 0 1 w 1 1 w<br /><br />I w w w 1 1 w<br /><br />J w 1 1 1 w 1<br /><br />K 0 1 0 w 0 1<br /><br />L 1 1 1 w w 0<br /><br />M w 1 1 w w w<br /><br />N w 1 1 1 w w<br /><br />O 0 w 0 1 w w<br /><br />P w w 1 w w w<br /><br />Q 1 w 0 w 1 1<br /><br />R 0 1 0 w w 1<br /><br />S 1 1 0 1 0 w<br /><br />T 1 1 1 1 w w<br /><br />U w w w w 1 1<br /><br />V w w w w w w<br /><br />X 1 0 w 0 w w<br /><br />Y w 0 1 1 w 1<br /><br />W 0 1 1 1 0 w<br /><br />Z 1 w 0</p>]]></description>
			<category>dr san</category>
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			<title>Reply #21</title>
			<link>https://www.lotterypost.com/thread/280103/3767844</link>
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			<pubDate>Sat, 06 Sep 2014 20:09:44 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello, Peer Gynt, remember, we are just seeing how you can<br /><br />Find a table of chaotic patterns, that can give us some Clues to pick3 well<br /><br />Let&#x27;s take the last five Sweepstakes pick3<br /><br />458<br /><br />852<br /><br />129<br /><br />360<br /><br />957<br /><br />Sort w = 0,1,2,3 O = 4.5 1 = 6,7,8,9<br /><br />Catch per vertical column = 4,8,1,3,9 = convert = o1ww1<br /><br />2 coluna = 5,5,2,6,5 = convert = 00w10<br /><br />3 coluna = 82,,9,0,7 convert 1w1w1<br /><br />We have three patterns, we can now use the 1st ching</p>]]></description>
			<category>dr san</category>
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			<title>Reply #20</title>
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			<pubDate>Sat, 06 Sep 2014 17:33:46 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>You and me both. The reasoning is not there for a Pick 3 game. Why would anyone want to take 30 possibilities and turn it into 64? Same with Pick 4. 36 possibilities is less than 64.<br /><br />Five times 9 = 45. 6 times 9 = 54. Still don&#x27;t see any use for increasing the possibilities.<br /><br />Seems like something to do if you have a lot of time to waste. And three days later it will be tossed aside like every other idea dr san posts.<br /><br />G</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #19</title>
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			<pubDate>Sat, 06 Sep 2014 14:43:02 GMT</pubDate>
			<dc:creator>PeerGynt</dc:creator>
			<description><![CDATA[<p>I&#x27;m having a hard time understanding this - maybe you can give a step-by-step example, Dr San?<br /><br />As to the hexagram example earlier... can you post a picture of a hexagram, with all of its sides, inside and out, accounted for? That would be an interesting angle, maybe there&#x27;s something to it.. it was once known as the Seal of Solomon, supposedly containing great and magical powers. Maybe it contained the secrets of numbers as well?...</p>]]></description>
			<category>PeerGynt</category>
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			<title>Reply #18</title>
			<link>https://www.lotterypost.com/thread/280103/3767454</link>
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			<pubDate>Sat, 06 Sep 2014 14:42:48 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello,TIA E CARBOB,can divide into eight patterns, positioning<br /><br />Or vertically in 3 positions on the eight standards pick3<br /><br />example<br /><br />Three closed lines are all combinations 000-999<br /><br />Pairs, 002, 0006, 4,6,8<br /><br />All open lines (odd) 000-999<br /><br />111.115, 5,9,7<br /><br />And so with after 6 standards, we have 8 patterns Represented in odd and even closed line (-----) pair, open line (---- -----) odd<br /><br />We clssificar the pick 3 8 patterns vertically positionally With these eight patterns</p>]]></description>
			<category>dr san</category>
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			<title>Reply #17</title>
			<link>https://www.lotterypost.com/thread/280103/3767408</link>
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			<pubDate>Sat, 06 Sep 2014 14:09:24 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, peergynt, what matters for another lottery pick 3 or is the division into parts, to build a lookup table<br /><br />Standards as vtrac, type a reductant, to see three digit positional Or pairs, a table that can help predict pick3 From 0-9, the filos ficam part does not help, what help<br /><br />It is the perfect table of 64 patterns, giving order to chaos</p>]]></description>
			<category>dr san</category>
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			<title>Reply #16</title>
			<link>https://www.lotterypost.com/thread/280103/3767359</link>
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			<pubDate>Sat, 06 Sep 2014 13:31:22 GMT</pubDate>
			<dc:creator>PeerGynt</dc:creator>
			<description><![CDATA[<p>You should use the sticks or the coins to see what they portend. The I-Ching, also known as the Book of Changes is a guide, not for number predictions.<br /><br />Or, better, the flight patterns of birds. Augury was the official Roman predictor-of-choice for many hundreds of years, at some points employing enough people to form a bureaucracy.<br /><br />Another very popular oracle tool for centuries, all through the Middle Ages, was Sortes Vergilianae - flipping to a random page of Virgil&#x27;s Aeneid, then taking... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/280103/3767359">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>PeerGynt</category>
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			<title>Reply #15</title>
			<link>https://www.lotterypost.com/thread/280103/3767358</link>
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			<pubDate>Sat, 06 Sep 2014 13:30:51 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, tia, and carbob, the 0-9 can be divided into three sectors<br /><br />K = 0,1,2, U = O = 3,4,5,6 7,8,9 three groups are in each position of pick3<br /><br />Closed line of the hexagram is even and odd line is open<br /><br />The hexagram with three closed lines is chosen a digit<br /><br />Each of the groups<br /><br />1 k = 0,1,2<br /><br />2 L = 3,4,5,6<br /><br />The 3rd = 7,8,9<br /><br />Hexagram 3 closed lines = 0,4,8 or 2,6,8 etc ...<br /><br />And so with other seven patterns, with this you can have control of the subgroups<br /><br />In each position, and se... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/280103/3767358">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #14</title>
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			<pubDate>Sat, 06 Sep 2014 12:39:16 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, Aunt, can separate into two half the digits 0-9 in 50/50 even and odd<br /><br />Low high outside in, or anyway it is divided into two parts<br /><br />Equal, then work subsets as in vtrac, to view the table of 64<br /><br />Emerging patterns, each giving evidence of other</p>]]></description>
			<category>dr san</category>
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			<title>Reply #13</title>
			<link>https://www.lotterypost.com/thread/280103/3767287</link>
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			<pubDate>Sat, 06 Sep 2014 12:17:39 GMT</pubDate>
			<dc:creator>tokecap</dc:creator>
			<description><![CDATA[<p>Powerball<br /><br />Winning Numbers 9/3/2014<br /><br />2 16 43 45 51 - 35</p>]]></description>
			<category>tokecap</category>
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			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/280103/3767271</link>
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			<pubDate>Sat, 06 Sep 2014 12:04:28 GMT</pubDate>
			<dc:creator>CARBOB</dc:creator>
			<description><![CDATA[<p>Tia,<br /><br />You never cease to amaze me, good thinking.</p>]]></description>
			<category>CARBOB</category>
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			<title>Reply #11</title>
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			<pubDate>Sat, 06 Sep 2014 11:48:53 GMT</pubDate>
			<dc:creator>Tialuvslotto</dc:creator>
			<description><![CDATA[<p>The 64 patterns are really combinations of 8 base patterns of 3 lines each. Maybe you could do something with Base 8</p>]]></description>
			<category>Tialuvslotto</category>
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			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/280103/3767070</link>
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			<pubDate>Sat, 06 Sep 2014 05:18:45 GMT</pubDate>
			<dc:creator>Coin Toss</dc:creator>
			<description><![CDATA[<p>You should use the sticks or the coins to see what they portend. The I-Ching, also known as the Book of Changes is a guide, not for number predictions.<br /><br />About I Ching (Yi Jing)...<br /><br />The I Ching, or Yi Jing, is one of the oldest known documents in the world.<br /><br />This Classic of Change can be traced as far back as 3000 years in written form, and the Chinese claim that it was passed down as oral tradition for two thousand years before that.<br /><br />Its longevity isn&#x27;t the only wonder the I Ch... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/280103/3767070">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Coin Toss</category>
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			<title>Reply #9</title>
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			<pubDate>Sat, 06 Sep 2014 03:12:09 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>link www1.uol.com.br/iching</p>]]></description>
			<category>dr san</category>
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			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/280103/3766940</link>
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			<pubDate>Sat, 06 Sep 2014 03:09:48 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello destinycreation<br /><br />link=https=<br /><br />I CHING - O Livro das Muta es</p>]]></description>
			<category>dr san</category>
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			<title>Reply #7</title>
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			<pubDate>Sat, 06 Sep 2014 01:16:47 GMT</pubDate>
			<dc:creator>PeerGynt</dc:creator>
			<description><![CDATA[<p>Oh, Destinycreation... there&#x27;s already only thousands of years worth of Eastern philosophers been trying to answer that question....</p>]]></description>
			<category>PeerGynt</category>
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			<title>Reply #6</title>
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			<pubDate>Sat, 06 Sep 2014 00:52:41 GMT</pubDate>
			<dc:creator>destinycreation</dc:creator>
			<description><![CDATA[<p>What do these 64 patterns mean</p>]]></description>
			<category>destinycreation</category>
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			<title>Reply #5</title>
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			<pubDate>Sat, 06 Sep 2014 00:49:58 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>Might interest some.<br /><br />I&#x27;m more interested in a grounded statistical approach based on real numbers that I can see and know what they mean. Reinventing the wheel is not necessary. Understanding the mechanics of how it works is.<br /><br />It&#x27;s your idea. Your system. Run with it and see where it takes you.<br /><br />G</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #4</title>
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			<pubDate>Sat, 06 Sep 2014 00:13:27 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, GARYO, 64 IS SMALLER THAN 1000 (MIL) !!<br /><br />MOTHERS subdivided into 64 groups in 15-16 pick3 also<br /><br />Can give evidence</p>]]></description>
			<category>dr san</category>
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			<title>Reply #3</title>
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			<pubDate>Fri, 05 Sep 2014 23:19:36 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>64 is more than 9. Why complicate things? Isn&#x27;t digits 0-9 enough to be concerned with?<br /><br />Not saying that offhand or without some experience. When I work with the Predator program I always find something that can be further explored in the 2Step game.</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #2</title>
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			<pubDate>Fri, 05 Sep 2014 21:19:57 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>64 patterns</p>]]></description>
			<category>dr san</category>
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			<title>Reply #1</title>
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			<pubDate>Fri, 05 Sep 2014 21:04:49 GMT</pubDate>
			<dc:creator>destinycreation</dc:creator>
			<description><![CDATA[<p>Explain the I-Ching</p>]]></description>
			<category>destinycreation</category>
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			<title>1&#xba; ching in lottery?</title>
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			<pubDate>Fri, 05 Sep 2014 20:46:22 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>How can we use the 64 standards of the 1st ching<br /><br />60/6 in a lottery? Or any other. Using only the last digit<br /><br />0-9</p>]]></description>
			<category>dr san</category>
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