Predictions from a sequence

Reply #19

dr san — Tue, 08 Dec 2015 22:14:29 GMT

Hello Monel you can do to 6 digits? As is done for 4 to possible patterns for rows with 6 strings

123456 000111 x = 000000

???? You can standards for six strings

Reply #18

AllenB — Wed, 02 Dec 2015 04:16:02 GMT

String Event

2

Frequency

3.5

Games Out

4

Draw

4

9

2

8

Singles

0127

0128

0178

0237

0238

0378

0247

0248

0478

0257

$63.00

0258

0578

0267

0268

0678

0279

0289

0789

1237

1238

Boxes Hit

1378

1247

1248

1478

1257

1258

1578

1267

1268

1678

1

1279

1289

1789

2347

2348

Reply #17

AllenB — Tue, 01 Dec 2015 23:48:02 GMT

Sorry for the pdf. I am still learning about displaying images images in my posts.

California Daily 4 Tonight.

This is what CA.pdf

Reply #16

AllenB — Tue, 01 Dec 2015 17:45:37 GMT

By the way, for Ca if I am correct I can still loose money when the Box payouts are very small

Reply #15

AllenB — Tue, 01 Dec 2015 17:39:47 GMT

Sorry for the delay in responding. Being Grampy to 3 beautiful little girls is just more important.

I am updating the sequence together with it's cousins to try to go a little further down Prediction Road.

The sequence posted so far was derived as follows:

The basic concept was to separate the numbers into 2 groups and track the hits from each group on every draw. Sound a lot like Strings? . My system is based on 4_Strings and The type of Draw (S,D,DD,T,Q).

Strings have the two gro... [ More ]

Reply #14

RL-RANDOMLOGIC — Fri, 27 Nov 2015 12:31:51 GMT

AllenB

If you find something that works let me know. When working with random data it's always possible to come

to a solution that looks more probable than the others. The most probable will hit more often overall but this

does not tell us when. The problem is further compounded when working with more than one string.

In the above example (0 45 2%) (1 299 11%) (2 792 29%) (3 1035 38%) (4 530 20%). If we add the totals

of 2 and 4 we get 49%, so the two combined are great... [ More ]

Reply #13

dr san — Fri, 27 Nov 2015 10:22:32 GMT

Hello Monel. The cracks and quadruple system could also be used in pick6 example

12 15 21 31 09 42 = 0,9,1,2,1,5,2,1,3,1,4,2

Trinca = 222

Quad = 1111

It has separate start and end digest

Monel the problem is how to locate the 12 positions?

Find the digit triune and quadruple

In the above example the formation in 1111 gave the positions = = 3 5 8th 10th

Using the five groups? 0000,0011,0001,0012,0123

Reply #12

MonEl — Fri, 27 Nov 2015 03:21:01 GMT

Whatever 0 is and or stands for (represents) it doesn't come out very often as seen on that short sequence, so maybe it is not a very likely pattern, but it can still come out next, same as with any other of those patterns.

Maybe the 0 = Quad (1111).

Reply #11

eddessaknight — Thu, 26 Nov 2015 22:34:43 GMT

OK Allen

How bouts 0 ???

Eddessa_Knight

Reply #10

MonEl — Thu, 26 Nov 2015 13:12:09 GMT

So my question was: Is there any way to ignore the method of creation and simply forecast from the sequence itself.

I do think so, but it might be a little harder to do maybe.

But in this case, at least to start with, you need to first study a much longer sequence of those digits-patterns, than maybe you would otherwise.

Either of the two ways, it might not be easy and or maybe even possible to do right, but Who knows?

Maybe with the Right prediction logic , prediction logic is... [ More ]

Reply #9

MonEl — Thu, 26 Nov 2015 13:00:18 GMT

34231334124324242421333232313332403242434423133444244232442423234223343242122113313322233042434244322244031312333322213232222333234234434210342323224323413231344241421333222243123323412323232332242231441134244221344444423133221323333344224022413213232412424322423441322312434331314144342423233212442124343334133112221343231333342241233434324324033344423232222342341234232323324243322233324332344443224434234443332333134142243424233333313133243224243234333323142342243233342021331334213323323424244334... [ More ]

Reply #8

Tialuvslotto — Thu, 26 Nov 2015 12:54:16 GMT

Basically, this problem comes down to a choice between 2 and 3. If you choose both of those you will be right about 2/3 of the time. So your choice becomes:

2, 3, neither 2 nor 3.

You might want to include 4 with the 2 and 3 -- with a median of 2 it hits almost as often and the larger group will hit 85% of the time, but at the cost of adding in an extra choice.

Reply #7

MillionsWanted — Thu, 26 Nov 2015 01:08:51 GMT

There is a function in Excel called Forecast . I've tested it on Keno with some luck.

Reply #6

adobea78 — Thu, 26 Nov 2015 00:01:34 GMT

Is a very good read, it may seem abstract, hence dry to some. It may seem abstract because the approach to most of the topics is more philosophical.

Reply #5

Tialuvslotto — Wed, 25 Nov 2015 16:40:38 GMT

If anyone is interested, I found this book online. I'm not sure I'd call it a good read . It is Fredette's doctoral thesis and as dry as you would expect.

https://uwspace.uwaterloo.ca/bitstream/handle/10012/1142/mfredett2004.pdf?sequence=1

Reply #4

adobea78 — Tue, 24 Nov 2015 23:33:35 GMT

A good read on 'Prediction of recurrent events by Marc Fredette' explains the concept of 'univariate to multivariate' in a random setting. If you subscribe to randomness(I infer from your text), then your assumption or line of reason should focus on that.

Reply #3

AllenB — Tue, 24 Nov 2015 16:59:00 GMT

In Excel, I have tracked Games out or Skips converted them to Frequencies and created large Charts that compared events side by side over past game blocks. I have looked at Followers, Skip Trends, etc. all of these processes produce a sequence of numbers that I can perform the same calculation for all over again. I don't know where the iterations end, probably never. It always proves that the Draws are Random. Every time I think the most frequent event will occur next it rarely does. My hope is... [ More ]

Reply #2

AllenB — Tue, 24 Nov 2015 14:21:02 GMT

The sequence was created by creating 2 groups of numbers. The R Group contains from 6 to 8 numbers depending on the Type of the last Draw (Single, Double, Double Double, Triple of Quadruple) The sequence is the count of numbers in the Draw from the R Group.

I was looking for some place to start to analyze the sequence, Theory?, Formulas? Excel Workout?

I will try your suggestions in Excel.

Thanks for the suggestion.

Reply #1

GoogilyMoogily — Tue, 24 Nov 2015 14:05:24 GMT

Need more info to answer your program or formula question.

Did you generate a sequence by (let's just say) took a certain number string from pi or e, then converted to hex, added your birthday, then

reduced the series into a spreadsheet quartile like this =QUARTILE(cell:cell,{0,1,2,3,4}), maybe by wrapping all that in a =MATCH(cell,value)?

This question gets asked routinely. Not sure what the point is.

Predictions from a sequence

AllenB — Mon, 23 Nov 2015 21:56:33 GMT

I have the following sequence of numbers.

3423133412432424242133323231333240324243442313344424423244242323422334324212211331332223304243424432224403131233332221323222233323423443421034232322432341323134424142133322224312332341232323233224223144113424422134444442313322132333334422402241321323241242432242344132231243433131414434242323321244212434333413311222134323133334224123343432432403334442323222234234123423232332424332223332433234444322443423444333233313414224342423333331313324322424323433... [ More ]