Breaking down Daily 4 a Preliminary Report

Reply #17

lakerben — Thu, 07 Jan 2016 17:42:28 GMT

5252 was the hit. Close!

Keep an eye out for the rest with this method.

Reply #16

Tialuvslotto — Thu, 07 Jan 2016 12:48:54 GMT

Games in Data 2743 Last Game 2777

R Hits Hits Frequency Games Out GO/F

1 305 9 21 234%

4 544 5 7 139%

3 1050 2.6 3 115%

2 802 3.4 1 29%

0 49 56 2 4%

Looking at the options, 0 can be eliminated for a few draws. I should noted that there are not that many combinations created from this option so it can be played for less than the other 4 options. Monitoring the Games out Divided by the Frequency shows which options are due or overdue.

With this decision there is a 1:5 Cha... [ More ]

Reply #15

lakerben — Wed, 06 Jan 2016 17:56:12 GMT

Hottest past 50 ca p4

2,4,7,9

then I add the adjacent number then a +111. Compare and then try some of these for 2 weeks.

2 4 7 9

3 5 8 0

5 9 15 9

6 0 6 0

7 1 7 1

8 2 8 2

9 3 9 3

0 4 0 4

1 5 1 5

2 6 2 6

3 7 3 7

4 8 4 8

5 9 5 9

6 0 6 0

Reply #14

AllenB — Wed, 06 Jan 2016 16:47:44 GMT

I new this was simple. I just could not resist making it complicated with Excel. Thanks for pointing this out. It was right there in front of me but I could not see it.

I will be posting how I have tracted positions, and multiples that use these groups.

Feeling Stupid but more enlightened, thanks

Reply #13

Tialuvslotto — Wed, 06 Jan 2016 16:40:28 GMT

Without involving strings, this can easily and quickly be broken down. The digits that hit in the last draw are the N group and the digits that did not hit in the last draw are the R group.

The trick is to decide how many of each will appear in the next combination.

Reply #12

AllenB — Wed, 06 Jan 2016 16:35:01 GMT

The first table show the setup to extract the broken strings.

the Second table show the current draw with the previous draws broken strings in the table. The row containing 0 or 10 is the count for each number in the table. 0 means not present (N), 10 means present (R

Reply #11

AllenB — Wed, 06 Jan 2016 16:15:45 GMT

Here is a way to determine the broken strings using Excel.

On Winsom's 4 Strings Sheet you will find the complete list of 4 Strings. There are 210 Strings based on numbers arranged in increasing order from left to right. In the first 4 columns left of the Broken Strings, in row above the first String enter the numbers from a draw. Under each number on the row for each string enter a formula that counts the number of times the draw number is present on the String Breakers for the each String... [ More ]

Reply #10

AllenB — Wed, 06 Jan 2016 15:34:18 GMT

The groups are formed by taking the broken Strings from the previous draw. As an example Game #2782 was a Single Draw (No matches) 7580. This Combination Broke 15 (4 Strings) as follows:

The String Numbers below are found in Winsom's String Excel Sheet (4 Strings)

Broken Strings by Number: 85,87,90,92,95,102,107,110,117,127,142,145,152,162and 182.

These 15 Strings contained 6 numbers 123469 These numbers become the R Group. Numbers not included in the 15 broken strings 0578. These numb... [ More ]

Reply #9

Tialuvslotto — Wed, 06 Jan 2016 13:34:37 GMT

Going back and reading your post on the math forum made this a lot clearer: https://www.lotterypost.com/thread/296288/2

I find this interesting, because I do something similar with skips.

Dividing the skips into Last game (skip 0), second last (skip 1), third last (skip 2), and fourth or more (skip 3+) gives a 'skip signature' for each drawing. About 75% of the time this will be 2110 or 3100. 1102,1201,2101,2011, 2110, 3001,3100,1003,3010,1300 account for about 2/3 of these or .67*.75=.50... [ More ]

Reply #8

phileight — Wed, 06 Jan 2016 12:18:18 GMT

AllanB interesting! tell us more. you said you select digits based on broken strings? I don't understand exactly how you are doing this.

Reply #7

AllenB — Wed, 06 Jan 2016 03:06:48 GMT

Reply #6

AllenB — Wed, 06 Jan 2016 01:44:27 GMT

OK Thanks for the alternative. I Looked at what you have. Did you Look at What I Posted? Any Ideas related to this process would be appreciated.

Reply #5

adobea78 — Wed, 06 Jan 2016 01:25:20 GMT

1.

A constant group 1234 has 16 front pairs considering P

A constant group 1234 has 6 pairs considering C with no repeat digits

A constant group 1234 has 10 pairs considering C with a repeat digits

2.

A constant group 1234 has 64 front triads considering P

A constant 1234 has 4 pairs considering C with no repeats

A constant 1234 has 20 pairs considering C with digit repeats

For 16 front pairs, you have 1600 picks/ draw

For 6 any pairs , you have 600 front pairs

Reply #4

adobea78 — Wed, 06 Jan 2016 01:08:14 GMT

The filter conditions depend on P or C of the binomial format NPr or NCr .

P= permutation, meaning repeated digits

C= Combination, meaning order is not important

One has to make a choice of sticking to P or C.

Reply #3

AllenB — Wed, 06 Jan 2016 01:02:42 GMT

So you Have a constant Group 1,2,3,4. What do you do to pick positions in the Draw

Reply #2

adobea78 — Wed, 06 Jan 2016 00:56:31 GMT

Keep things simple, P4 has 10000 combos:

1.Locate front pairs for 100picks

2.Locate front triad for 10 picks

3.Locate any pair for x picks (do the calculation)

4.Locate any triad x picks( do the calcuation)

Using the binomial format 10P4 you can filter 3,4.

Focusing on 1,2,3,4 is all you need, waging is personal choice.

Reply #1

AllenB — Wed, 06 Jan 2016 00:30:23 GMT

The Combinations vary depending on the R Count and the R Hit for each game. The post is only applicable to a game with an R Count of 7 and hit count 2. I will follow up with the other combinations soon.

Breaking down Daily 4 a Preliminary Report

AllenB — Wed, 06 Jan 2016 00:09:29 GMT

I have posted a little bit about this process previously in the Mathematics Forum under the Topic Predictions from a Sequence .

Divide and Conquer is the General idea behind the approach.

Playing Daily 4 only requires 4 choices, one for each number.

Decision 1 (Pick First Number) has 10 possible options as do each succeeding Decision. I replace the first decision with an option that has only 5 options. The 5 options are the number of hits expected from 1 of 2 groups of numbers. General... [ More ]