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		<title>strings cartezian</title>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/325548/5843002</link>
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			<pubDate>Thu, 21 Feb 2019 14:12:26 GMT</pubDate>
			<dc:creator>Todd</dc:creator>
			<description><![CDATA[<p></p>]]></description>
			<category>Todd</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/325548/5842882</link>
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			<pubDate>Thu, 21 Feb 2019 09:57:18 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>ok, you have to use blocks of 3 last pick3 vertically and horizontally, you can use<br /><br />the vertical RL system 312 .... in each position<br /><br />you can use to create a duplicate of the pick3 from the left of the carteziano cross ex = we have 9 digits in the matrix of the last 3 drawings<br /><br />if you cross row with columns we have 4 remaining digits to draw a double<br /><br />or do 3x3x3 = 27 of this I repeat a digit in each position</p>]]></description>
			<category>dr san</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/325548/5842873</link>
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			<pubDate>Thu, 21 Feb 2019 09:38:04 GMT</pubDate>
			<dc:creator>Soledad</dc:creator>
			<description><![CDATA[<p>Yes I ve looked at these this way i knew not what it s called ,I have three that I look at all the time. Go on please see what you can maybe I could look furthur. strings</p>]]></description>
			<category>Soledad</category>
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			<title>strings cartezian</title>
			<link>https://www.lotterypost.com/thread/325548</link>
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			<pubDate>Thu, 21 Feb 2019 09:16:19 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>you can use the last 3 raffles of the pick3<br /><br />ex =<br /><br />451<br /><br />602<br /><br />459<br /><br />1st vertical position = 464 2nd position 505 3rd position 129<br /><br />last draw = 459<br /><br />in each block of the last three raffles we have 4 pick3 generated<br /><br />one in the horizontal (last draw) and three in the vertical of each position will be generated then 3 pick3 to play, you can use the Cartesian crossing<br /><br />ABC<br /><br />451 1<br /><br />602 2<br /><br />459 3<br /><br />a1 = 451464 remaining = 023789<br /><br />a2 = 464602<br /><br />.....<br /><br />c3 = 129451<br /><br />we have 9... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/325548">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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