find all combinations of 6 numbers from 20 numbers PS script

Reply #5

timmsy — Tue, 12 Jan 2021 11:15:30 GMT

here is another example on how to use the script so my keno is 1..80 , i like playing 5 number

1..40 fine 3 numbers

41..80 find 2 numbers

so its 2 function and 2 foreach loops to loop all combinations of 5 numbers until 41..80 is completed

I had a win

I didn't add the script to look in past results and find the most common 5 hits but lets say from 400 past keno games using this script I found 5 numbers came up 15 times, SO i played the 5 numbers for $1 bet for 200 games that's... [ More ]

Reply #4

timmsy — Tue, 12 Jan 2021 09:36:20 GMT

thanks

Bobp and cottoneyedjoe its a stepping stone for anything ,

if you have an Idea to find wining lotto numbers it can be scripted you may not win the big one but you will win a small

Reply #3

BobP — Tue, 12 Jan 2021 06:32:05 GMT

Sweet, but if you posted this in the Systems forum the thread will remain visible longer, won't get pushed off the page as quickly.

BobP

Reply #2

cottoneyedjoe — Tue, 12 Jan 2021 00:38:32 GMT

Nice scripts Timmsy.

Reply #1

timmsy — Mon, 11 Jan 2021 10:59:38 GMT

you could filter the 20 numbers to look for 3 odd 3 even or 4 odd 2 even to save time

add

$oddn = ($df.Split( , ) | % {if($_ % 2 -eq 1 ) { $_ | sort} }) -join ( , ) # odd

$evenn = ($df.Split( , ) | % {if($_ % 2 -eq 0 ) { $_ | sort} }) -join ( , ) #even

$even1 = $evenn.Split( , )

$odd1 = $oddn.Split( , )

$countod = @($odd1).Count

$countev = @($even1).Count

and do a if statement and a little more code

the the total 12320 combinations of 6 numbers from 2... [ More ]

find all combinations of 6 numbers from 20 numbers PS script

timmsy — Mon, 11 Jan 2021 10:19:17 GMT

the script to find all combinations of 6 numbers from 20 numbers

#################################################################################################

$newArray= 1,2,3,4,10,6,7,8,9,5,23,44,45,21,11,27,22,12,13,15| sort | group

for($i=0; $i -lt $newArray.Count; $i++){

for($j=$i+1; $j -lt $newArray.Count; $j++){

for($k=$j+1; $k -lt $newArray.Count; $k++){

for($l=$k+1; $l -lt $newArray.Count; $l++){

for($h=$l+1; $h -lt $newArray.Count; $h++){

for($a=$h+1; $a -lt