how to use the statistical universe in lotteries?

Reply #23

Speler — Mon, 17 May 2021 17:50:16 GMT

The same way we did 20/70.

11978571669969891796072783721689098736458938142546425857555362864628009582789845319680000000000000000 / ( 2432902008176640000 * 30414093201713378043612608166064768844377641568960512000000000000 ) = 161884603662657876

And p(20/70) = 1 / 161884603662657876

= 6.1772396965176698315325041317696716782897830280198856598579302991260104348843680264E-18

Reply #22

Speler — Mon, 17 May 2021 17:33:40 GMT

So the function to calculate the count of the combinations is n!/((n-p)!*p!). You agree with that, you learned it that way, you said: Yes, I understand! . Okay.

119622220865480194561963161495657715064383733760000000000/(20397882081197443358640281739902897356800000000*14686475098462159218221002852730086096896000000000)=8145060

6 out of 45 jackpot = 1 IN 8145060

Reply #21

Speler — Sun, 16 May 2021 09:11:31 GMT

Sorteio realizado no Espa o Loterias Caixa em SÃO PAULO, SP

01 04 05 06 07 08 10 11 16 18 19 20 22 24 25

Wheel result:

8 5

9 8

10 8

11 3 * 5 R$

12 1 * 10 R$

Cost for one line: 2.5 R

Reply #20

dr san — Sun, 16 May 2021 00:04:04 GMT

hello speller, the prize is 11,12,13,14,15 points and 15 points is the maximum prize

the lottery is 01 to 25 with 15 numbers drawn

in the post above we have some sweepstakes, the main thing is to find a way to filter by the veen graph (because it is a filter without conflict

Reply #19

Speler — Sat, 15 May 2021 22:13:30 GMT

6/45

h w c 6 score

0 6 0 0

6 0 0 1

0 0 6 2

1 0 5 4

5 0 1 6

1 5 0 6

0 1 5 7

5 1 0 8

0 5 1 8

2 4 0 12

0 4 2 16

4 2 0 17

4 0 2 17

0 2 4 17

2 0 4 18

3 0 3 19

0 3 3 22

3 3 0 25

1 4 1 31

1 1 4 36

4 1 1 43

3 1 2 70

1 3 2 73

1 2 3 83

3 2 1 85

2 1 3 91

2 3 1 112

2 2 2 116

hcw determined by an algorithm. 15 numbers by group.

Reply #18

Speler — Sat, 15 May 2021 17:30:43 GMT

One drawing is missing.

What are the payouts?

Play this?

1 2 3 5 8 10 12 14 15 16 17 18 21 22 23

1 2 3 6 8 13 15 16 17 18 20 22 23 24 25

1 2 3 9 10 11 12 13 15 18 21 22 23 24 25

1 2 4 6 7 8 9 12 14 15 16 18 21 22 25

1 3 6 7 8 9 11 12 15 16 18 20 21 23 24

1 3 7 10 12 15 16 17 19 20 21 22 23 24 25

1 4 5 7 8 13 15 16 18 19 20 21 22 23 24

1 4 6 8 9 10 12 15 18 19 20 22 23 24 25

1 5 7 8 9 10 12 13 14 16 18 22 23 24 25

1 7 8 11 12 13 14 15 17 18 1... [ More ]

Reply #17

dr san — Sat, 15 May 2021 16:33:59 GMT

hello draws 25/15

02 03 05 06 09 10 11 13 14 16 18 20 23 24 25

01 04 05 06 07 09 11 12 13 15 16 19 20 23 24

01 04 06 07 08 09 10 11 12 14 16 17 20 23 24

01 02 04 05 08 10 12 13 16 17 18 19 23 24 25

01 02 04 08 09 11 12 13 15 16 19 20 23 24 25

01 02 04 05 06 07 10 12 15 16 17 19 21 23 25

01 04 07 08 10 12 14 15 16 18 19 21 22 23 25

01 05 06 08 09 10 13 15 16 17 18 19 20 22 25

03 04 05 09 10 11 13 15 16 17 19 20 21 24 25

02 03 04 05 06 08 09 10 11 1... [ More ]

Reply #16

Speler — Sat, 15 May 2021 09:05:36 GMT

I use the hot group to play for 1000 games.

1000*combin(15,6)*-1.25

=-6252506 EUR

A 6/6 mostly pays one million but the amount could be shared with another winner. A payout of several million euros is rare.

I can play 15 numbers with a systems form. I mark 15 numbers.

Reply #15

Speler — Sat, 15 May 2021 08:44:39 GMT

The author didn't define his hwc.

Hot is like 30 degrees Celsius and cold is like -18 degrees Celsius.

Reply #14

Speler — Sat, 15 May 2021 08:35:49 GMT

6/45

3 groups of 15 numbers.

15 15 15 Combin Combin Combin Product * Order p 1/p

2 2 2 105 105 105 1157625 0.14 7.04

3 2 1 455 105 15 4299750 0.53 1.89

3 3 0 455 455 1 621075 0.08 13.11

4 1 1 1365 15 15 921375 0.11 8.84

4 2 0 1365 105 1 859950 0.11 9.47

5 1 0 3003 15 1 270270 0.03 30.14

6 0 0 5005 1 1 15015 0 542.46

Check SUM: 8145060

Fractions rounded: 0.00

Reply #13

BobP — Sat, 15 May 2021 05:57:06 GMT

Agreed it is possible all the winning numbers can all come from one, two or all three groups, though it is 2-2-2 that is most probable.

http://web.archive.org/web/20050126053842/http://www.geocities.com/wallstreet/7746/hwc.html

BobP

Reply #12

Speler — Fri, 14 May 2021 22:17:41 GMT

speller, my lottery (one of them) uses from 01 to 25 where 15 numbers (lotofacil) are drawn, can you put some filters on the graph of veenbes

You need 15 numbers. You have A union B so far. Do you have 15 numbers

Reply #11

Speler — Fri, 14 May 2021 22:01:44 GMT

A = {2; ... }

B = {3; ... }

A B = {6; ... }

6 mod 2 == 0 6 mod 3 == 0

6 ...

Reply #10

dr san — Fri, 14 May 2021 18:44:20 GMT

https://en.wikipedia.org/wiki/File:Venn3tab.svg

Reply #9

dr san — Fri, 14 May 2021 18:42:19 GMT

Set A: numbers divisible by 2

2,4,6,8,10,12,14,16,18,20,22,24

Set B: numbers divisible by 3

3,6,9,12,15,18,21,24

Overlap:

6,12,18,24

en.wikipedia.org/wiki/Venn_diagram

pt.wikipedia.org/wiki/Diagrama_de_Venn

Using two filters and a 2-circle venn diagram, you'll need three numbers:

The hit ratio of the first filter, the hit ratio of the second filter, and the hit ratio of both filters when used together.

The first ratio goes in one crescent, the second goe... [ More ]

Reply #8

Speler — Fri, 14 May 2021 18:07:00 GMT

I want to see your veenbes graph on a worked out case.

Reply #7

dr san — Fri, 14 May 2021 12:27:38 GMT

hello speller, to avoid conflict in the lottery filters you must create the veen chart! OK! in fact speller is a good job, it is to make the graph of veen to avoid conflict in the lottery filters

Reply #6

Speler — Fri, 14 May 2021 12:07:21 GMT

You can do the opposite, you filter first and reduce afterwards by picking lines of running a program to keep a coverage, as you probably fail to do good by picking. And you forget about the graph.

Reply #5

Speler — Fri, 14 May 2021 11:52:44 GMT

John Venn's? You can can draw it in your paintshop pro or in paint.exe

Reply #4

dr san — Fri, 14 May 2021 11:20:37 GMT

hello speller, but defaults is a way to reduce and then filter by columns, well then we can use the veen graph, to avoid conflict in the filters

Reply #3

Speler — Fri, 14 May 2021 09:07:06 GMT

Three groups? The winning numbers can come from one, two or all three groups. If you add more patterns, they all must be right to win the first prize. It would be simpler to pick the correct numbers immediately and not think about patterns

Reply #2

Stat$talker — Fri, 14 May 2021 08:30:19 GMT

Don't think it can be said any better.!!.. But be careful, there are some here that would have you demonstrate that, with 1 hand tied behind your back, both eyes closed, while using a broken calculator..!!.. Has to do with some sorta Challenge thing..

Reply #1

BobP — Fri, 14 May 2021 05:52:59 GMT

I'm not touching the statistical universe thingie beyond saying it's an eliptoid spheroid full of combinations.

Hot cold is not ideal, you want hot, average, cold and it's just a filter set among many that improve your chances when correct and eliminate them when wrong.

BobP

how to use the statistical universe in lotteries?

dr san — Fri, 14 May 2021 00:59:27 GMT

how to use the statistical universe in lotteries?

is the hot cold parameter ideal, or do we need to cross more strategies