My Method explained

Reply #15

Sandy K — Fri, 12 Mar 2004 10:29:18 GMT

Come on, blush a little..

Reply #14

CalifDude — Fri, 12 Mar 2004 10:10:16 GMT

Ah shucks

Reply #13

Sandy K — Fri, 12 Mar 2004 09:37:58 GMT

The Dude is alright in my

Reply #12

LARRY G — Fri, 12 Mar 2004 09:26:08 GMT

Very good....and this system...is free....!Who says you must buy a lottery program....create your own..or fine tune...the one you have.I tip my hat to CalifDude

Reply #11

CalifDude — Fri, 12 Mar 2004 05:44:12 GMT

You are very welcome. Hope we can improve on it.CalifDude

Reply #10

EXCALIBUR — Fri, 12 Mar 2004 05:43:10 GMT

Thank you for all of this, I will read it and hope that I can understand it.Thank you very much again.

Reply #9

Blackapple — Fri, 12 Mar 2004 05:42:38 GMT

Thanks for sharing ,if I get it;good for me;if I don't, for nowthats ok,but I'm forever gratefulyou took the (your) time to shareyour method in your way.

Reply #8

CalifDude — Fri, 12 Mar 2004 02:32:46 GMT

Oh, and for doubles..look at this interesting info: Double 1= 3 4 3 2= 2 0 1 3= 2 2 2 4= 2 1 2 5= 4 9 8 6= 2 3 0 7= 4 0 1 8= 4 0 3 9= 2 4 3 0= 0 2 2This shows that for doubles only that the first position is most of the time, position 5, 7, or 8 (of the 10 number sequence). The middle number is most of the time position 5 and the third number is most often position 5.Also: Hits Double 1= 11 2= 3 3= 6 4= 5 5= 20 6= 5 7= 5 8= 7 9= 9 0= 4Remember that the numbers in the first column above relate t... [ More ]

Reply #7

CalifDude — Fri, 12 Mar 2004 02:22:46 GMT

So, you make a decision which one you want to play. I use a spreadsheet that I have made up to do most of the work for me. Here is the first part of the sheet for tonight's draw: 9 9 2 4 2 9 2 3 8 9 2 6 7 9 2 1 0 9 2 5 4 9 8 4 3 9 8 3 6 9 8 6 1 9 8 1 5 9 8 5 9 7 4 9 7 3 9 7 6 9 7 1 9 7 5 9 0 4 9 0 3 9 0 6 9 0 1 9 0 5The top left is where I put in the 10 digits in order and the spreadsheet does the rest of the work.So, how do we reduce the numbers down? I use the column skip method or you can... [ More ]

Reply #6

CalifDude — Fri, 12 Mar 2004 02:08:12 GMT

Here are the results, going back about 100 draws of the numbers in the last column (1-2, 2-1, etc.): (0-3)= 4 (1-2)= 4 (2-1)= 7 (3-0)= 10 0-3= 6 1-2= 28 2-1= 28 3-0= 6 Total = 93 Again, the () indicates a double. At the top of the list is (0-3) meaning zero numbers from the first group of 5 and all 3 numbers from the second group of 5 and it was a double. Only 4 of those in the last 93 draws.Let's turn our attention to 1-2 and 2-1. These are the most drawn, and that is not a surprise. I ha... [ More ]

Reply #5

CalifDude — Fri, 12 Mar 2004 01:56:24 GMT

Now that I have my 10 digits in order, what does that do for me? Well I have analyzed how those positions have been drawn in the past. Num 0 1 2 3 4 5 6 7 8 9 928 1 3 1 2 2 8 3 1 3 4 4844 03/11 mid 19 72043-86195 926 1-2 720 1 2 4 1 1 7 2 5 2 3 4843 03/10 eve 9 04386-19275 981 1-2 043 11 1 3 2 4 6 1 4 1 2 4842 03/10 mid 7 86193-24750 075 1-2 861 10 1 2 1 3 5 4 3 7 1 4841 03/09 eve 15 93124-76580 973 1-2 931 9 11 1 1 2 4 3 2 6 1 4840 03/09 mid 13 23947-65801 320 2-1 239 8 10 4 1 1 3 2 1 5 2 483... [ More ]

Reply #4

CalifDude — Fri, 12 Mar 2004 01:36:12 GMT

Let me now just copy a few numbers: Number 0 1 2 3 4 5 6 7 8 9 2 4 1 3 3 9 4 2 1 1 4845 03/11 eve 928 1 3 1 2 2 8 3 1 3 4 4844 03/11 mid 720 1 2 4 1 1 7 2 5 2 3 4843 03/10 eve 043 11 1 3 2 4 6 1 4 1 2 4842 03/10 midI write down the numbers in order without duplicating (Ohiopick3 method). So for tonights draw I start with 928, looking at the next number (720), I see that only the 2 has been used, so I write down the 70...my number now is 92870-. I write a dash between the first set of 5 and the... [ More ]

Reply #3

CalifDude — Fri, 12 Mar 2004 01:25:38 GMT

Now to get to the meat of my method. This method will produce 75 numbers, or 50 without doubles. But it will not hit every time and therefor needs to be reduced. I suggest playing box, not straight or straight/box because it will not pay off enough to get back what you have lost! I will show you how I reduce the amount of numbers to 23, which is playable (a box in California averages about $100). You can reduce it further, but also reducing your odds of winning. I'm hoping that enough peop... [ More ]

Reply #2

CalifDude — Fri, 12 Mar 2004 01:12:30 GMT

Here is the data for the sums columns in California: Num col skip 928 03/11 mid 19 0 5=11 720 03/10 eve 9 +2 +4=10 043 03/10 mid 7 +2 +3=14 861 03/09 eve 15 -2 +2=17 931 03/09 mid 13 -1 +1=19 239 03/08 eve 14 0 0=15 473 03/08 mid 14 0 -1=17 969 03/07 eve 24 -4 -2=20 576 03/07 mid 18 +1 -3=10 962 03/06 eve 17 -1 -4=24 648 03/06 mid 18 +1 467 03/05 eve 17 -4 399 03/05 mid 21 +4 980 03/04 eve 17 -2 270 03/04 mid 9 -1 271 03/03 eve 10 0 343 03/03 mid 10 0 109 03/02 eve 10 0 190 03/02 mid 10 +3The fi... [ More ]

Reply #1

CalifDude — Fri, 12 Mar 2004 01:01:14 GMT

One way of picking numbers (not really my method, but I will use this info to reduce the amount of numbers I play) is to try to pick the column that will hit on the next draw and play those 22 numbers. Or you can reduce the 22 numbers to only 9 by only playing those numbers that have neighbors. By neighbors I mean two numbers in sequence (12, 56, and please note that 09 is a neighbor) and they can be in any order. So with a number like 150, there is a neighbor (01). Here is a chart of the 22... [ More ]

My Method explained

CalifDude — Fri, 12 Mar 2004 00:54:15 GMT

Let me start by defining some terms I use. When I talk about a sum, that is the sum of the three digits and dropping the tens digit, if there is one. So, the number 105 has a sum of 6, the number 646 also has a sum of 6 (16 = 6), and 899 has a sum of 6 (26 = 6). This divides the 220 possbile unique numbers into 10 equal columns of 22 numbers each. 0 1 2 3 4 5 6 7 8 9 000 001 002 003 004 005 006 007 008 009 019 029 011 012 013 014 015 016 017 018 028 038 039 049 022 023 024 025 026 027 037 047... [ More ]