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		<title>Calif 5/17 Midday China Method</title>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/87486/208278</link>
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			<pubDate>Mon, 17 May 2004 21:23:49 GMT</pubDate>
			<dc:creator>CalifDude</dc:creator>
			<description><![CDATA[<p>Calif Midday = 285 ... a miss in both charts.</p>]]></description>
			<category>CalifDude</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/87486/208165</link>
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			<pubDate>Mon, 17 May 2004 14:35:10 GMT</pubDate>
			<dc:creator>CalifDude</dc:creator>
			<description><![CDATA[<p>No..have to get to bed...will do the other 4 states that I do starting for Friday Midday, posted on Thursday night.</p>]]></description>
			<category>CalifDude</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/87486/208152</link>
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			<pubDate>Mon, 17 May 2004 14:21:21 GMT</pubDate>
			<dc:creator>Lady_g98</dc:creator>
			<description><![CDATA[<p>are u going to post texas</p>]]></description>
			<category>Lady_g98</category>
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			<title>Calif 5/17 Midday China Method</title>
			<link>https://www.lotterypost.com/thread/87486</link>
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			<pubDate>Mon, 17 May 2004 14:18:10 GMT</pubDate>
			<dc:creator>CalifDude</dc:creator>
			<description><![CDATA[<p>1673 (Row A) 3920 (Row B) 0854 (Row C) Modified 1673 (Row A) 6985 (Row B) 1204 (Row C)Take one digit from each row to make up your 3-digit number.  If you do all of them, you will come up with 64 tickets (4X4X4 = 64).  The  modified  rows are modified sequence for this state only and are designed to maximize your chance of a straight.I&#x27;m still looking for doubles.  Not many in my China Method, so you may want to find something else or do the couple of doubles in this chart.  You might want to se... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/87486">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>CalifDude</category>
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