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		<title>pick 3 probability</title>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/87694/209667</link>
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			<pubDate>Fri, 21 May 2004 23:30:04 GMT</pubDate>
			<dc:creator>interceptor</dc:creator>
			<description><![CDATA[<p>dont buy a bunch of ticketsinstead, find the pattern and follow itthis leads to less tickets and more winnings</p>]]></description>
			<category>interceptor</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/87694/209220</link>
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			<pubDate>Thu, 20 May 2004 20:04:24 GMT</pubDate>
			<dc:creator>Bertil</dc:creator>
			<description><![CDATA[<p>Thank you Jake,Your formula yields practically the same result as e-^r, where r=ratio of number of tickets to 1000. E.g.for 5000 tickets the value becomes :0.006738.Bertil</p>]]></description>
			<category>Bertil</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/87694/209218</link>
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			<pubDate>Thu, 20 May 2004 19:58:51 GMT</pubDate>
			<dc:creator>Bertil</dc:creator>
			<description><![CDATA[<p>Quote: Originally posted by Jake649 on May 20, 2004Quote: Originally posted by Bertil on May 20, 2004 By what formula does one calculate the odds of winning a pick3 type game if one buys 100 random tickets? Would it be 10%?Suppose the lottery sells only 5000 random tickets, what % of all numbers are likely to remain not sold?If every one of the 100 tickets is unique, then the odds of winning are exactly 10%. If you buy quick picks, you may have one or more duplicates, so the odds of winning are</p>]]></description>
			<category>Bertil</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/87694/209180</link>
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			<pubDate>Thu, 20 May 2004 17:00:38 GMT</pubDate>
			<dc:creator>Jake649</dc:creator>
			<description><![CDATA[<p>Quote: Originally posted by Bertil on May 20, 2004 By what formula does one calculate the odds of winning a pick3 type game if one buys 100 random tickets? Would it be 10%?Suppose the lottery sells only 5000 random tickets, what % of all numbers are likely to remain not sold?If every one of the 100 tickets is unique, then the odds of winning are exactly 10%. If you buy quick picks, you may have one or more duplicates, so the odds of winning are 9.5%.The formula is (1-p)^N where p = the probabili... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/87694/209180">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Jake649</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/87694/209171</link>
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			<pubDate>Thu, 20 May 2004 16:24:48 GMT</pubDate>
			<dc:creator>RJOh</dc:creator>
			<description><![CDATA[<p>Bertil,A pick 3 game include combinations 000-999 which is 1000 combinations.  When combinations are picked randomly, there is no guarantee of coverage no matter the number of combinations picked.  If the lottery sells 5000 random tickets, the odds are pretty good that all the combinations are covered, but that is not a guarantee that it actually happened.  If you are going to buy 100 tickets and you want to make sure you don&#x27;t play any combinations twice, you probably should pick them yourself... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/87694/209171">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>RJOh</category>
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			<title>pick 3 probability</title>
			<link>https://www.lotterypost.com/thread/87694</link>
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			<pubDate>Thu, 20 May 2004 15:31:23 GMT</pubDate>
			<dc:creator>Bertil</dc:creator>
			<description><![CDATA[<p>By what formula does one calculate the odds of winning a pick3 type game if one buys 100 random tickets? Would it be 10%?Suppose the lottery sells only 5000 random tickets, what % of all numbers are likely to remain not sold?Bertil</p>]]></description>
			<category>Bertil</category>
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