even odd question

Reply #36

lottoarchitect — Wed, 15 Sep 2004 00:34:21 GMT

This feature included in the program. I got the percentages from it. The real question is how to interpret such information and go a bit further in order to eliminate with confidence some patterns.

Reply #35

JKING — Mon, 13 Sep 2004 14:32:54 GMT

apagogas.That sure would be a great feature in your progam, knowing the error percentages and the greater likely hood of some filter criteria when making your choices.

Reply #34

lottoarchitect — Mon, 13 Sep 2004 12:35:31 GMT

We can't eliminate any odd/even pattern easily.The important thing to notice is that some parrerns have much better chance to appear than others. In a 6/49 game these are:OOEOEO, OEOOEO, OEOEOO, OEOEOE, OEOEEO, OEEOEO, EOEOEOThe above 7 patterns (out of 64 total) have a 2.12% chance to occur.On the other hand, there are patterns that have much less chance to occur. These are:EEEEEE - 0.96%21 patterns provide 1.27% chance to occurand the remaining patterns have 1.65% chance to occur.Your error is... [ More ]

Reply #33

trance — Sat, 11 Sep 2004 14:45:09 GMT

You can replace the first and third E with O,and there would be OEOOOE

Reply #32

Fenix — Sat, 11 Sep 2004 12:54:10 GMT

Still cant get it.What is with OEOOOE for example missing 4 in your lines

Reply #31

trance — Sat, 11 Sep 2004 11:23:57 GMT

Quote: Originally posted by Fenix on September 11, 2004Quote: Originally posted by trance on September 10, 2004 Those ones are ok.They are OK for what?Ok for a better chance to bet on odd and even pattern only if you knew the first and third line are the same E OR O .

Reply #30

Fenix — Sat, 11 Sep 2004 07:42:55 GMT

Quote: Originally posted by trance on September 10, 2004 Those ones are ok. They are OK for what

Reply #29

trance — Fri, 10 Sep 2004 11:36:10 GMT

E O E E O E E O E E E O E E E E O E E E E E E O E E E E E E E O E E E E E O E O O E E O E O E O E E E O O E E E E O E O E E E O E E E O E O E E Those ones are ok.

Reply #28

UCI1 — Thu, 09 Sep 2004 19:10:32 GMT

Quote: Originally posted by trance on September 09, 200442 lines that almost covers all possibilities. O O O E E O E O E E O E E O E E E O E E E E O E O O O E E E O E E E E E E E E E E O E E E E E E E E E E E E E E E E E E E E E E O E O O E E E E E O E E E O E O E E E E E E E E E O E O E E E E E O E E E E E O E E O E E O E E E O E E E E E O E O E E E O O O O O E O

Reply #27

trance — Thu, 09 Sep 2004 14:55:57 GMT

42 lines that almost covers all possibilities. O O O E E O E O E E O E E O E E E O E E E E O E O O O E E E O E E E E E E E E E E O E E E E E E E E E E E E E E E E E E E E E E O E O O E E E E E O E E E O E O E E E E E E E E E O E O E E E E E O E E E E E O E E O E E O E E E O E E E E E O E O E E E O O O O O E O E O E O O E E O E O E O E E E O O E O

Reply #26

UCI1 — Tue, 07 Sep 2004 03:52:50 GMT

The idea was to look to see which odd/even patterns would be the best to use when making combinations using all 49 numbers also, which high/low patterns would be the best to use. There are 20 3/3 odd/even patterns and 15 2/4 patterns and 15 4/2 patterns. That's 50 odd/even patterns to make combinations with.I had just gotten started working on this and had to turn my attentions toward other things so I have never went much farther than making the charts.

Reply #25

JKING — Tue, 07 Sep 2004 02:17:37 GMT

Let me try to get this all in perspective.If you opt to use odd/even as a reduction criteria for selecting your final lottery numbers. How many combinations for example would be eleminated if you chose 0/6-6/6 and what error % would you introduce into your selection process.Food for another discussion is what are acceptable error %'s? What yeilds the smallest error% with the greatest amount of reductions?...

Reply #24

UCI1 — Mon, 06 Sep 2004 18:11:24 GMT

Quote: Originally posted by MrSteel01 on September 06, 2004Better yet how many 0's AND 1's 2's 3's 4's 5'5 6's 7's 8's 9's DIGIHTS/NUMBERS are there in 220 or 1,000 boxes and or combinations? Each per say!That way you can find out what digit/numbers that are the most of that should come in the most over all!Sorry, I don't work with Pick3 or Pick4 games.By the way MrSteel01, your Private Inbox is full and can not accept messages at this time.... [ More ]

Reply #23

UCI1 — Mon, 06 Sep 2004 18:06:25 GMT

Quote: Originally posted by Fenix on September 03, 2004Quote: Originally posted by UCI1 on August 21, 2004 If anyone would like to look at an odd/even pattern chart it can be found here http://psl.4mg.com/oddevenchart.html. You can also see an odd/even and low/high breakdown of the record holding 49n, 3if6in163c wheel http://psl.4mg.com/493if6in163.html.UCI1, what happened with your charts?If anyone would like the odd/even chart for the 6/49 or the 49#, 3if6in163c send me a private message with

Reply #22

MrSteel01 — Mon, 06 Sep 2004 15:34:11 GMT

Better yet how many 0's AND 1's 2's 3's 4's 5'5 6's 7's 8's 9's DIGIHTS/NUMBERS are there in 220 or 1,000 boxes and or combinations? Each per say!That way you can find out what digit/numbers that are the most of that should come in the most over all

Reply #21

Fenix — Fri, 03 Sep 2004 09:40:24 GMT

Quote: Originally posted by UCI1 on August 21, 2004 If anyone would like to look at an odd/even pattern chart it can be found here http://psl.4mg.com/oddevenchart.html. You can also see an odd/even and low/high breakdown of the record holding 49n, 3if6in163c wheel http://psl.4mg.com/493if6in163.html.UCI1, what happened with your charts

Reply #20

lottoarchitect — Sun, 22 Aug 2004 15:47:47 GMT

I got lost too

Reply #19

UCI1 — Sat, 21 Aug 2004 12:54:58 GMT

Quote: Originally posted by Fenix on August 21, 2004It was a kind unclear before , but Im absolutely confused now . I cant see any covering here For instance, meant for 6odd/0even, 0low/6high the numbers 25,27,29,31,33,35,37,39,41 and so on, are not covered in any way.The numbers 1-24 were just an example that would only produce one combination each. The point is that to cover at least one combination each of 0/6 6/0 o/e and 0/6 6/0 L/H you would have to have a balance set of 24 numbers cont... [ More ]

Reply #18

Fenix — Sat, 21 Aug 2004 12:21:10 GMT

________________________________________________________QUOTE: Originally posted by UCI1 on August 21, 2004I was wrong, it should be 12 odd numbers and 12 even numbers, a total of 24 numbers.6odd/0even, 6low/0high - 1, 3, 5, 7, 9, 11. 6odd/0even, 0low/6high - 13, 15, 17, 19, 21, 23.0odd/6even, 6low/0high - 2, 4, 6, 8, 10, 12. 0odd/6even, 0low/6high - 14, 16, 18, 20, 22, 24.No matter what the pool size is or what numbers are being played, if you want to cover an o/e of 0/6 and 6/0 and cover the L... [ More ]

Reply #17

UCI1 — Sat, 21 Aug 2004 11:39:48 GMT

I was wrong, it should be 12 odd numbers and 12 even numbers, a total of 24 numbers.6odd/0even, 6low/0high - 1, 3, 5, 7, 9, 11. 6odd/0even, 0low/6high - 13, 15, 17, 19, 21, 23.0odd/6even, 6low/0high - 2, 4, 6, 8, 10, 12. 0odd/6even, 0low/6high - 14, 16, 18, 20, 22, 24.No matter what the pool size is or what numbers are being played, if you want to cover an o/e of 0/6 and 6/0 and cover the L/H of 0/6 and 6/0 it will take at least 12 odd numbers and 12 even numbers and 12 low and 12 high numbers.

Reply #16

Fenix — Sat, 21 Aug 2004 10:43:25 GMT

________________________________________________________QUOTE:What I had left out of the last post was the fact that it takes at least 12 numbers to cover an o/e of 0/6 6/0 and still cover the low/high patterns (6 even and 6 odd numbers) the odd/even must be of equal balance.________________________________________________________This is still quite vague. Can you please explain the approach where 12 numbers cover an o/e of 0/6 6/0 and still cover the low/high patterns

Reply #15

UCI1 — Sat, 21 Aug 2004 09:05:20 GMT

If anyone would like to look at an odd/even pattern chart it can be found here http://psl.4mg.com/oddevenchart.html. You can also see an odd/even and low/high breakdown of the record holding 49n, 3if6in163c wheel http://psl.4mg.com/493if6in163.html.

Reply #14

UCI1 — Sun, 15 Aug 2004 12:33:24 GMT

Quote: Originally posted by UCI1 on August 13, 2004If you choose say only 18 numbers to wheel in a pick 6 and and use the full o/e spectrum 0/6, 1/5, 2/4, 3/3, 4/2, 5/1, 6/0 and taking into consideration the 7 low/high patterns, not all of the o/e patterns will be used as the amount of numbers being used will not allow this to be possible.So far what I have found is that it takes at least 12 numbers to cover an o/e of 0/6-6/0 and still cover the low/high patterns also. If my calculations are cor... [ More ]

Reply #13

UCI1 — Fri, 13 Aug 2004 20:39:32 GMT

Quote: Originally posted by apagogeas on August 13, 2004UCI1, if you've downloaded my program, you can go to Rejection filters -> Pattern odd/even. There you'll see all 64 possible categories and their % to appear (or their combination size). You should know that the % of each category may differ from another one. If you want to find the % of eg 5 odd 1 even category, you have to add the rates of all respective categories.What do you mean by your last question?If you choose say only 18 numbers t... [ More ]

Reply #12

lottoarchitect — Fri, 13 Aug 2004 16:12:32 GMT

UCI1, if you've downloaded my program, you can go to Rejection filters -> Pattern odd/even. There you'll see all 64 possible categories and their % to appear (or their combination size). You should know that the % of each category may differ from another one. If you want to find the % of eg 5 odd 1 even category, you have to add the rates of all respective categories.What do you mean by your last question

Reply #11

UCI1 — Thu, 12 Aug 2004 11:09:25 GMT

I have another question concerning the odd/even combinational balance. How many numbers would it take to cover all 64 odd/even combinational distrubutions in a pick 6, at least one time

Reply #10

UCI1 — Thu, 12 Aug 2004 10:50:24 GMT

In a pick 6 playing all combinations of odd/even 0/6 thru 6/0 there are 64 chances of having 0 or 6 in the correct positions. There are 384 chances of having 1 or 5 in the correct positions. There are 960 chances of having 2 or 4 in the correct positions and there are 1280 chances of having 3 in the correct positions.This is not taking account for actual numbers but odd/even positions only.I am understanding a little more now as I can see why the term odds came about when talking chance. The act... [ More ]

Reply #9

dragon — Tue, 10 Aug 2004 23:16:33 GMT

Oh, yes, Pascal's triangle.Sometimes I love math. I get these books that talk about all these wonderful properties, I read them, marvel at them, and promptly forget about them again. What better place to use this stuff than here.

Reply #8

UCI1 — Tue, 10 Aug 2004 21:04:05 GMT

I think that the even/odd combinational distrubution says it all as in Pascal's triangle. e/o bal...............0/6 1/5 2/4 3/3 4/2 5/1 6/0 hits possible.......00 - 01 - 02 - 03 - 04 - 05 - 06match possibles ..01 06 15 20 15 06 01No matter which single even/odd combinational distrubution that is played out of the 64 possible, the chances of matching are 1, 6, 15, 20, 15, 6, 1.

Reply #7

JKING — Tue, 10 Aug 2004 13:26:59 GMT

Dragon, Sharing is a win-win. And gives away nothing about my system finally selects numbers for the next draw. Like most others here, it's a work in progress.Anyway taking the Pick 3 odd/even distribution, the calculations are simple. Just write down all the possible odd/even combinations like below. Divide the combination group by the total amount of combinations that can be generated times 100 and your on your way.What's interesting about this is-if you decide to eliminate the All Odd and Al... [ More ]

Reply #6

UCI1 — Tue, 10 Aug 2004 09:18:41 GMT

Very nice JKING, your summary sheet is great, thanks. It was also pointed out to me in another group that the totals appear in the 6th row of Pascal's triangle.11 2 11 3 3 11 4 6 4 11 5 10 10 5 11 6 15 20 15 6 1Or, 2^6. (The nth row of Pascal's triangle sums to 2^n.

Reply #5

dragon — Tue, 10 Aug 2004 04:42:17 GMT

JKING:Where the heck did you get this stuff and how did you compute it?I just looked as UCI's numbers, saw they were binary, figured there are 2^6, and then manually looked for where he had duplicated any. I would not know how to calculate these the way you did.

Reply #4

JKING — Tue, 10 Aug 2004 02:00:16 GMT

Hi, It's been a long time since I've seen your name. I don't know if this will help:Odd/Even Distribution Summary SheetPick 3 Odd/Even Distribution Combinations By PercentageAll Odd112.5All Even112.51-Odd 2-Even337.537.52-Odd 1-Even337.537.5Total =8100.075.0Pick 4 Odd/Even Distribution Combinations By PercentageAll Odd16.25All Even16.251-Odd 3-Even425253-Odd 1-Even425252-Odd 2-Even637.537.5Total =16100.087.5Pick 5 Odd/Even Distribution Combinations By PercentageAll Odd13.... [ More ]

Reply #3

dragon — Sun, 08 Aug 2004 04:18:35 GMT

Quote: Originally posted by UCI1 on August 08, 2004Thanks dragon, now that I know that there are duplicates, I'm wondering if I'm missing any combinations?No, you're not missing any combinations. There are a total of 64. Take out the duplicates, and there are 64 left. That's it.

Reply #2

UCI1 — Sun, 08 Aug 2004 04:13:42 GMT

Thanks dragon, now that I know that there are duplicates, I'm wondering if I'm missing any combinations

Reply #1

dragon — Sun, 08 Aug 2004 03:43:23 GMT

Quote: Originally posted by UCI1 on August 07, 2004I was wondering if anybody knows the amount of possible combinations in eacheven/odd balance?Here is what I have come up with and I'm just trying to confirm if I amcorrect or if I have made any mistakes.ODD - EVEN6/0 - 0/6 has 2 possible combinations6/0 - O O O O O O0/6 - E E E E E E5/1 - 1/5 has 12 possible combinations, 6 for each.5/1 - O O O O O E O O O O E O O O O E O O O O E O O O O E O O O O E O O O O O1... [ More ]

even odd question

UCI1 — Sun, 08 Aug 2004 02:31:28 GMT

I was wondering if anybody knows the amount of possible combinations in eacheven/odd balance?Here is what I have come up with and I'm just trying to confirm if I amcorrect or if I have made any mistakes.ODD - EVEN6/0 - 0/6 has 2 possible combinations6/0 - O O O O O O0/6 - E E E E E E5/1 - 1/5 has 12 possible combinations, 6 for each.5/1 - O O O O O E O O O O E O O O O E O O O O E O O O O E O O O O E O O O O O1/5 - E E E E E O E E E E O E E E E O E... [ More ]