Hello and a question

Reply #12

fox_91 — Fri, 24 Sep 2004 15:37:51 GMT

yeh that site does it, it thinks of 0 as the high number i always thought of it as a low number. but it is rather simple to do with 3 and 4 numbers.

Reply #11

CalifDude — Fri, 24 Sep 2004 10:25:22 GMT

There is also some web site where someone tries to get you to buy their system and it is based on the same idea...pick one number only and win the prize!! It has been discussed on LotteryPost many times.

Reply #10

LANTERN — Fri, 24 Sep 2004 08:21:31 GMT

1 2 3 4 5 6 7 8 9 0 0 1 2 0 1 2 0 1 3 0 1 4 0 1 5 0 1 6 0 1 7 0 1 8 0 1 9 0 1 20 1 3 0 2 3 0 2 3 0 2 4 0 2 5 0 2 6 0 2 7 0 2 8 0 2 9 0 1 30 1 4 0 2 4 0 3 4 0 3 4 0 3 5 0 3 6 0 3 7 0 3 8 0 3 9 0 1 40 1 5 0 2 5 0 3 5 0 4 5 0 4 5 0 4 6 0 4 7 0 4 8 0 4 9 0 1 50 1 6 0 2 6 0 3 6 0 4 6 0 5 6 0 5 6 0 5 7 0 5 8 0 5 9 0 1 60 1 7 0 2 7 0 3 7 0 4 7 0 5 7 0 6 7 0 6 7 0 6 8 0 6 9 0 1 70 1 8 0 2 8 0 3 8 0 4 8

Reply #9

fox_91 — Fri, 24 Sep 2004 02:41:15 GMT

well for some reason my code seems broke so until i figure it out i can post the algebra of it.the basic idea for pick 3 would be (no repeat) C = constant (user chosen)C, C+1, (C+1)+1 for C <= 9 if repeat C, C, C then increment from there. the same equation would work with 4 or 5 numbers, u simply have more so for exampleif u wanted to play the 1's with out repeat it would start1(C) 2(C+1) 3[(C+1)+1] so it would follow to this124, 125, 126, 127, 128, 129. then when the last number reaches the de... [ More ]

Reply #8

Blackie — Fri, 24 Sep 2004 01:39:32 GMT

Has anyone tried to use the 1 key number that is most overdue or hasnt shown for the past 5 days or so ? I've sometimes split them up as key # - eeo or key # ooe as I'm sure alot on here may have used. Here's the ones for 5. Hope they dont take up too much space Blackie Key # 5 Key # 5580 567584 561568 578562 572504 503582... [ More ]

Reply #7

JKING — Fri, 24 Sep 2004 00:12:35 GMT

I'm not sure I've any FULLY published system here. Just bit's and pieces of everybodys.About that key number, it might be more acheivable than you think. All I'll say is that's a work in progress with favorable results showing up more and more frequently.I would love to see what your doing.

Reply #6

fox_91 — Thu, 23 Sep 2004 20:49:33 GMT

are there any topics posted that deal with this? i was taking a quick look thru the posts but didn't see anything yet that shows a system like this.

Reply #5

LANTERN — Thu, 23 Sep 2004 20:40:06 GMT

As for getting the one key digit for the pick 3, I can't do it yet, but it appears that there are a few forum members here that do know how to get the one digit often, some of them more often than others.That it can be done, yes it can, if not always, then very often, I have seen some people here do it and often.Good luck.

Reply #4

fox_91 — Thu, 23 Sep 2004 17:53:12 GMT

i guess i didnt finish my response to ur question lantern. yes the system i came up with is along the lines of what u said, i always looked at my system for pick 3 like this. u pick the one group number and then the system would generate a list of all number non-redundant combonations from that number up (it could work with duplicates or not) so like for example if u played the 5 group u would play567,568,569,578,579,589 if u played for non-repeating numbers (or if with repeating u would write... [ More ]

Reply #3

fox_91 — Thu, 23 Sep 2004 13:08:02 GMT

yeh that would about sum it up, i can generate the tables for pick 3,4,5,6 it gets a little large on pick 5 for lower numbers. i don't really think there is any way to pick that 1 number other than being lucky. im trying to work with it to let people pick 2 numbers but generating the list is slightly more difficult then. if i can get the program finished to a working point i will let u know.

Reply #2

LANTERN — Thu, 23 Sep 2004 07:01:29 GMT

Are you talking about picking 1 key number and buying 36 singles (no doubles nor triples) if yes, then we already know about this.If doubles also then there would be 20 more and triples then 10 more for a total of 66 boxed or any order numbers (combos), 56 of them without the triples.But for this to work you have to pick one of the 3 digits of the next winning pick 3 number, if you pick the wrong digit or key number then you throw away $56 at $1 for number (combo).Do you have a system for getti... [ More ]

Reply #1

retxx — Thu, 23 Sep 2004 02:02:29 GMT

hi fox,welcome and on lottery post all ideas are welcomed by all who post here. Anything that has potential is always tried by many and are thankful to the one who offers it especially when it is free for all to try. happy lottering.

Hello and a question

fox_91 — Thu, 23 Sep 2004 01:39:25 GMT

hi, i just found your forumns and want to first say hello. a little background before i post my question. im a college student (junior) and am interested in finding ways to beat the system. in this year i figured out a blackjack system for online casinos but that is neither here nor there, when i was a junior in high school i developed this system on easter sunday, it was simple and only worked with pick 3 lottery, i won and then tried to implemnt it to larger pots. i just now finaly have a beta... [ More ]