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		<title>Odd/Even Calculations</title>
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		<description>Lottery Post Forum Topic: Odd/Even Calculations</description>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/97452/265924</link>
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			<pubDate>Fri, 08 Oct 2004 13:18:06 GMT</pubDate>
			<dc:creator>johnph77</dc:creator>
			<description><![CDATA[<p>Agreed. There will always be an imbalance between odd and even numbers in any game where there are an odd number of choices to be made regardless of the amount of numbers drawn no matter how many numbers are drawn. The same holds true, for instance, in a 6/49 game, albeit with slightly different percentages. And, unless 0 (zero) is used as a starting point, the imbalance will always be favoring the odd numbers. Good start.gljohn</p>]]></description>
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			<title>Odd/Even Calculations</title>
			<link>https://www.lotterypost.com/thread/97452</link>
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			<pubDate>Fri, 08 Oct 2004 08:41:20 GMT</pubDate>
			<dc:creator>JKING</dc:creator>
			<description><![CDATA[<p>Using 0&#x27; s and 1&#x27;s like the sample below does not give an accurate representation of an odd/even distribution.Pick 5 Odd/Even Distribution  All Odd100000All Even1111111-Odd   4-Even4-Odd   1-Even1000011111102000102111013001003110114010004101115100005011112-Odd   3 Even3-Odd   2-Even10001111110020010121101030100131011041000140111050011051100160101061010171001070110180110081001191010090101110110001000111  Combinations    By PercentageAll Odd13.125All Even13.1251-Odd   4-Even515.6254-Odd   1-Even51... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/97452">More</a>&#xa0;&#x5d;</p>]]></description>
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