Man finds winning numbers in strings of PI (Video)Prev Topic Next Topic

New Topic New Poll

grwurston

100

Same digits. Different games.

United States
Member #90,245
April 24, 2010
16,864 Posts
Online

Oct 22, 2012, 11:39 pm

Quote: Originally posted by n11201966 on Oct 22, 2012
hi onlymoney i love this great theory u have,but i dont understand it to much where do you put in the old draw numbers to get the winning numbers. by the way love the stuff you and carlig post thanks alot .

Look on page 5 of the thread. Just past the cow.

When playing the lottery the thing that should matter the most is: Are you winning more than you spend? Good Luck!!!

Kola

Rookie Time Traveler

Milky Way Spiral
United States
Member #28,944
December 25, 2005
1,657 Posts
Offline

Oct 23, 2012, 3:34 pm

Hello Onlymoney,

Great thread. You might also like this:

I once posted a thread about looking for the Pick 3 draws in the Pi string. https://www.lotterypost.com/thread/148644 If you look at the bottom of the first page, I produced a portion of the Pi string and highlighted some interesting parts. I chose the finality of "999999" as the end of my string, partly because of its "six-y circleness", and determined that I'd look for Pick 3 results in only the numbers that came before it.

By the way, in "999999" the "first 9" is the 763th digit in the Pi string and the "last 9" is the 768th.

Its interesting if you add the first 12 numbers of the Fibbonaci sequence you get 376

1+1+2+3+5+8+13+21+34+55+89+144 = 376

And,

If you add the second 12 numbers you get 137

233+377+610+987+1597+2584+4181+6765+10946+17711+28657+46368 = 121016

Numerically reduce 121016 to its 3 digit nuber by subtracting 999 (121 times) from it or 016 +121= 137.

(Tangentially if you add 376 +137 = 513....may be of use...)

I also determined that if I were to use the Fibbonaci sequence to look for Pick 3 results, I 'd only look in the first 24 numbers partially because, looking at infinty would drive me a little insane, and they repeat after the first 24 numbers anyway. According to Jain of http://www.jainmathemagics.com/page/2/default.asp

Jain's Website info:

The Fibonacci series has a pattern that repeats every 24 numbers

Numeric reduction is a technique used in analysis of numbers in which all the digits of a number are added together until only one digit remains. As an example, the numeric reduction of 256 is 4 because 2+5+6=13 and 1+3=4.

A mathematician by the name of Jain discovered that applying numeric reduction to the Fibonacci series produces an infinite series of 24 repeating digits:

1, 1, 2, 3, 5, 8, 4, 3, 7, 1, 8, 9, 8, 8, 7, 6, 4, 1, 5, 6, 2, 8, 1, 9

If you take the first 12 digits and add them to the second twelve digits and apply numeric reduction to the result, you find that they all have a value of 9.

1st 12 numbers	1	1	2	3	5	8	4	3	7	1	8	9
2nd 12 numbers	8	8	7	6	4	1	5	6	2	8	1	9
Numeric reduction - Add rows 1 and 2	9	9	9	9	9	9	9	9	9	9	9	18
Final numeric reduction - Add digits of result	9	9	9	9	9	9	9	9	9	9	9	9

We would expect a pattern to exist in the Fibonacci series since each number in the series encodes the sum of the previous two. What's not quite so obvious is why this pattern should repeat every 24 numbers or why the first and last half of the series should all add to 9.

For those of you from the "Show Me" state, this pattern of 24 digits is demonstrated in the numeric reduction of the first 73 numbers of the Fibonacci series, as shown below:

Fibonacci Number	Numeric reduction by adding digits
Fibonacci Number	1st Level	2nd Level	Final Level
Example: 2,584	2+5+8+4=19	1+9=10	1+0=1

0	0	0	0
1	1	1	1
1	1	1	1
2	2	2	2
3	3	3	3
5	5	5	5
8	8	8	8
13	4	4	4
21	3	3	3
34	7	7	7
55	10	1	1
89	17	8	8
144	9	9	9
233	8	8	8
377	17	8	8
610	7	7	7
987	24	6	6
1,597	22	4	4
2,584	19	10	1
4,181	14	5	5
6,765	24	6	6
10,946	20	2	2
17,711	17	8	8
28,657	28	10	1
46,368	27	9	9
75,025	19	10	1
121,393	19	10	1
196,418	29	11	2
317,811	21	3	3
514,229	23	5	5
832,040	17	8	8
1,346,269	31	4	4
2,178,309	30	3	3
3,524,578	34	7	7
5,702,887	37	10	1
9,227,465	35	8	8
14,930,352	27	9	9
24,157,817	35	8	8
39,088,169	44	8	8
63,245,986	43	7	7
102,334,155	24	6	6
165,580,141	31	4	4
267,914,296	46	10	1
433,494,437	41	5	5
701,408,733	33	6	6
1,134,903,170	29	11	2
1,836,311,903	35	8	8
2,971,215,073	37	10	1
4,807,526,976	54	9	9
7,778,742,049	55	10	1
12,586,269,025	46	10	1
20,365,011,074	29	11	2
32,951,280,099	48	12	3
53,316,291,173	41	5	5
86,267,571,272	53	8	8
139,583,862,445	58	13	4
225,851,433,717	48	12	3
365,435,296,162	52	7	7
591,286,729,879	73	10	1
956,722,026,041	44	8	8
1,548,008,755,920	54	9	9
2,504,730,781,961	53	8	8
4,052,739,537,881	62	8	8
6,557,470,319,842	61	7	7
10,610,209,857,723	51	6	6
17,167,680,177,565	67	13	4
27,777,890,035,288	73	10	1
44,945,570,212,853	59	14	5
72,723,460,248,141	51	6	6
117,669,030,460,994	65	11	2
190,392,490,709,135	62	8	8
308,061,521,170,129	46	10	1
498,454,011,879,264	72	9	9

Thanks to Helga Hertsig for being the first to bring Jain's discovery of this patternDto my attention.

Happy explorations,

Kola

The Ancient Lottery LoreKeeper replied, "A past draw lies at the centerpoint of a circle - a black hole. Two overlapping circles whose centerpoints sit on the circumference of the other share a Common Radius. This Radius is a Wormhole, a Time Machine. It allows the past draw (info) to safely travel into and beyond the present draw's event horizon without negative distortion, thereby creating an entanglement (synchrony) between the two communicating draws. This entangled space or portal is the Vesica Piscis - the white hole or Stargate through which the next draw is born."

onlymoney

United States
Member #128,782
June 2, 2012
5,431 Posts
Offline

Oct 23, 2012, 3:42 pm

Quote: Originally posted by Kola on Oct 23, 2012

Hello Onlymoney,

Great thread. You might also like this:

By the way, in "999999" the "first 9" is the 763th digit in the Pi string and the "last 9" is the 768th.

Its interesting if you add the first 12 numbers of the Fibbonaci sequence you get 376

1+1+2+3+5+8+13+21+34+55+89+144 = 376

And,

If you add the second 12 numbers you get 137

233+377+610+987+1597+2584+4181+6765+10946+17711+28657+46368 = 121016

Numerically reduce 121016 to its 3 digit nuber by subtracting 999 (121 times) from it or 016 +121= 137.

(Tangentially if you add 376 +137 = 513....may be of use...)

Jain's Website info:

The Fibonacci series has a pattern that repeats every 24 numbers

A mathematician by the name of Jain discovered that applying numeric reduction to the Fibonacci series produces an infinite series of 24 repeating digits:

1, 1, 2, 3, 5, 8, 4, 3, 7, 1, 8, 9, 8, 8, 7, 6, 4, 1, 5, 6, 2, 8, 1, 9

If you take the first 12 digits and add them to the second twelve digits and apply numeric reduction to the result, you find that they all have a value of 9.

1st 12 numbers	1	1	2	3	5	8	4	3	7	1	8	9
2nd 12 numbers	8	8	7	6	4	1	5	6	2	8	1	9
Numeric reduction - Add rows 1 and 2	9	9	9	9	9	9	9	9	9	9	9	18
Final numeric reduction - Add digits of result	9	9	9	9	9	9	9	9	9	9	9	9

For those of you from the "Show Me" state, this pattern of 24 digits is demonstrated in the numeric reduction of the first 73 numbers of the Fibonacci series, as shown below:

Fibonacci Number	Numeric reduction by adding digits
Fibonacci Number	1st Level	2nd Level	Final Level
Example: 2,584	2+5+8+4=19	1+9=10	1+0=1

0	0	0	0
1	1	1	1
1	1	1	1
2	2	2	2
3	3	3	3
5	5	5	5
8	8	8	8
13	4	4	4
21	3	3	3
34	7	7	7
55	10	1	1
89	17	8	8
144	9	9	9
233	8	8	8
377	17	8	8
610	7	7	7
987	24	6	6
1,597	22	4	4
2,584	19	10	1
4,181	14	5	5
6,765	24	6	6
10,946	20	2	2
17,711	17	8	8
28,657	28	10	1
46,368	27	9	9
75,025	19	10	1
121,393	19	10	1
196,418	29	11	2
317,811	21	3	3
514,229	23	5	5
832,040	17	8	8
1,346,269	31	4	4
2,178,309	30	3	3
3,524,578	34	7	7
5,702,887	37	10	1
9,227,465	35	8	8
14,930,352	27	9	9
24,157,817	35	8	8
39,088,169	44	8	8
63,245,986	43	7	7
102,334,155	24	6	6
165,580,141	31	4	4
267,914,296	46	10	1
433,494,437	41	5	5
701,408,733	33	6	6
1,134,903,170	29	11	2
1,836,311,903	35	8	8
2,971,215,073	37	10	1
4,807,526,976	54	9	9
7,778,742,049	55	10	1
12,586,269,025	46	10	1
20,365,011,074	29	11	2
32,951,280,099	48	12	3
53,316,291,173	41	5	5
86,267,571,272	53	8	8
139,583,862,445	58	13	4
225,851,433,717	48	12	3
365,435,296,162	52	7	7
591,286,729,879	73	10	1
956,722,026,041	44	8	8
1,548,008,755,920	54	9	9
2,504,730,781,961	53	8	8
4,052,739,537,881	62	8	8
6,557,470,319,842	61	7	7
10,610,209,857,723	51	6	6
17,167,680,177,565	67	13	4
27,777,890,035,288	73	10	1
44,945,570,212,853	59	14	5
72,723,460,248,141	51	6	6
117,669,030,460,994	65	11	2
190,392,490,709,135	62	8	8
308,061,521,170,129	46	10	1
498,454,011,879,264	72	9	9

Thanks to Helga Hertsig for being the first to bring Jain's discovery of this patternDto my attention.

Happy explorations,

Kola

Thanks.

Both links don't work for me.

Kola

Rookie Time Traveler

Milky Way Spiral
United States
Member #28,944
December 25, 2005
1,657 Posts
Offline

Oct 23, 2012, 3:50 pm

Quote: Originally posted by onlymoney on Oct 23, 2012
Thanks.

Both links don't work for me.

The links should work now. If they don't, just copy/paste

The Ancient Lottery LoreKeeper replied, "A past draw lies at the centerpoint of a circle - a black hole. Two overlapping circles whose centerpoints sit on the circumference of the other share a Common Radius. This Radius is a Wormhole, a Time Machine. It allows the past draw (info) to safely travel into and beyond the present draw's event horizon without negative distortion, thereby creating an entanglement (synchrony) between the two communicating draws. This entangled space or portal is the Vesica Piscis - the white hole or Stargate through which the next draw is born."

Kola

Rookie Time Traveler

Milky Way Spiral
United States
Member #28,944
December 25, 2005
1,657 Posts
Offline

Oct 23, 2012, 5:06 pm

Quote: Originally posted by Kola on Oct 23, 2012

Hello Onlymoney,

Great thread. You might also like this:

By the way, in "999999" the "first 9" is the 763th digit in the Pi string and the "last 9" is the 768th.

Its interesting if you add the first 12 numbers of the Fibbonaci sequence you get 376

1+1+2+3+5+8+13+21+34+55+89+144 = 376

And,

If you add the second 12 numbers you get 137

233+377+610+987+1597+2584+4181+6765+10946+17711+28657+46368 = 121016

Numerically reduce 121016 to its 3 digit nuber by subtracting 999 (121 times) from it or 016 +121= 137.

(Tangentially if you add 376 +137 = 513....may be of use...)

Jain's Website info:

The Fibonacci series has a pattern that repeats every 24 numbers

A mathematician by the name of Jain discovered that applying numeric reduction to the Fibonacci series produces an infinite series of 24 repeating digits:

1, 1, 2, 3, 5, 8, 4, 3, 7, 1, 8, 9, 8, 8, 7, 6, 4, 1, 5, 6, 2, 8, 1, 9

If you take the first 12 digits and add them to the second twelve digits and apply numeric reduction to the result, you find that they all have a value of 9.

1st 12 numbers	1	1	2	3	5	8	4	3	7	1	8	9
2nd 12 numbers	8	8	7	6	4	1	5	6	2	8	1	9
Numeric reduction - Add rows 1 and 2	9	9	9	9	9	9	9	9	9	9	9	18
Final numeric reduction - Add digits of result	9	9	9	9	9	9	9	9	9	9	9	9

For those of you from the "Show Me" state, this pattern of 24 digits is demonstrated in the numeric reduction of the first 73 numbers of the Fibonacci series, as shown below:

Fibonacci Number	Numeric reduction by adding digits
Fibonacci Number	1st Level	2nd Level	Final Level
Example: 2,584	2+5+8+4=19	1+9=10	1+0=1

0	0	0	0
1	1	1	1
1	1	1	1
2	2	2	2
3	3	3	3
5	5	5	5
8	8	8	8
13	4	4	4
21	3	3	3
34	7	7	7
55	10	1	1
89	17	8	8
144	9	9	9
233	8	8	8
377	17	8	8
610	7	7	7
987	24	6	6
1,597	22	4	4
2,584	19	10	1
4,181	14	5	5
6,765	24	6	6
10,946	20	2	2
17,711	17	8	8
28,657	28	10	1
46,368	27	9	9
75,025	19	10	1
121,393	19	10	1
196,418	29	11	2
317,811	21	3	3
514,229	23	5	5
832,040	17	8	8
1,346,269	31	4	4
2,178,309	30	3	3
3,524,578	34	7	7
5,702,887	37	10	1
9,227,465	35	8	8
14,930,352	27	9	9
24,157,817	35	8	8
39,088,169	44	8	8
63,245,986	43	7	7
102,334,155	24	6	6
165,580,141	31	4	4
267,914,296	46	10	1
433,494,437	41	5	5
701,408,733	33	6	6
1,134,903,170	29	11	2
1,836,311,903	35	8	8
2,971,215,073	37	10	1
4,807,526,976	54	9	9
7,778,742,049	55	10	1
12,586,269,025	46	10	1
20,365,011,074	29	11	2
32,951,280,099	48	12	3
53,316,291,173	41	5	5
86,267,571,272	53	8	8
139,583,862,445	58	13	4
225,851,433,717	48	12	3
365,435,296,162	52	7	7
591,286,729,879	73	10	1
956,722,026,041	44	8	8
1,548,008,755,920	54	9	9
2,504,730,781,961	53	8	8
4,052,739,537,881	62	8	8
6,557,470,319,842	61	7	7
10,610,209,857,723	51	6	6
17,167,680,177,565	67	13	4
27,777,890,035,288	73	10	1
44,945,570,212,853	59	14	5
72,723,460,248,141	51	6	6
117,669,030,460,994	65	11	2
190,392,490,709,135	62	8	8
308,061,521,170,129	46	10	1
498,454,011,879,264	72	9	9

Thanks to Helga Hertsig for being the first to bring Jain's discovery of this patternDto my attention.

Happy explorations,

Kola

Mistake: To look at the Mapping of Pi in the first link, go to the bottom of the 2nd page, not the 1st

lakerben

50

New Mexico
United States
Member #86,094
January 29, 2010
30,587 Posts
Offline

Oct 23, 2012, 6:47 pm

Quote: Originally posted by Kola on Oct 23, 2012
Mistake: To look at the Mapping of Pi in the first link, go to the bottom of the 2nd page, not the 1st

I ran across this the other day. Interesting.

Win!
WOODY99

JERSEY
United States
Member #115,205
August 15, 2011
7 Posts
Offline

Oct 24, 2012, 8:59 pm

Been playing around with this for NJ - ive been entering the 2 previous evening results in the Search For screen 774 & 051 then hit find next.

Don't have copy & paste in Mozilla but is what came out to the right of the Search for#.

774051 1398900507493228007

& look for the previous midday was 900.

the following midday was 704.

Pretty neat. Will keep testing

Mid 740

Eve 774

Mid 900

Eve 051
Jonusl

Galena,MO
United States
Member #129,320
June 15, 2012
101 Posts
Offline

Oct 28, 2012, 9:07 am

I've been tinkering with this as well in the state of missouri,what ive found is the following:

checking 10-27 evening draw i use 10-26 evening hit which was 452.i used the first 2 # mirrors,thus

came out with 902,which i put in the Pi search,First thing ive noticed about alot of the hits from missouri using

this is that on that FIRST string i look for pairs lots of 6's lets say or what ever,then i look around the 6 to see

whats its hugging,ect.then i goto the second,thrid ect click,usally on the second the hot pair or number is not there as much or sometimes not at all,but returns in the third click,and usally by the 3rd,4th click,somethings upto 6,7 the number will be in the string,that hits for the draw im looking at.going back to the,mirror i made above using Only the evening hit from 10-26,so evening to evening,miday to miday seems to work in mo,i came up with 902 and first string had sever 6's some 2's and a couple other numbers of notice,but narrows it down some,by i believe the 3rd click there it was on the left of the 902. 602 902 ,the 602 being a str8 hit for 10-27 in mo.the str8 hit dosnt seem to happen alot but the number does appear often next to or close to the number i was searching with,and withen the first 6 or less clicks.yeah.

The Dream Master says:Keep on dream'en,Dream'in of a win.........Because Dreams do come true
pamelab

north carolina/virginia
United States
Member #2,097
August 17, 2003
130 Posts
Offline

Oct 30, 2012, 11:33 am

I just plugged this into my spreadsheet where I had been playing around with PI, so for the heck of it yesterday's number in NC Day was 847 so I use the simple version of PI in spreadsheet =3.14*847, i get 265958, last nights number was 959, the mate for 595.
lakerben

50

New Mexico
United States
Member #86,094
January 29, 2010
30,587 Posts
Offline

Oct 30, 2012, 1:11 pm

I found something interesting. I used a recent draw 123 from NM.

I put in as 123678876. The draw,mirror,total. There were 2 starights on the left side 294, and 460 that came up.

Win!
msjthewinner

Wilmington, NC
United States
Member #130,023
July 4, 2012
207 Posts
Offline

Nov 4, 2012, 3:59 pm

Ok, just came across this thread and tried it for NC - I used the

last 2 draws as input: 026516

11/3/12 Day - 026

11/3/12 Eve - 516

Hitting the "find next" button 5 times gave today's midday (11/4/12)

number as an exact match 837

The string 026516 occurs at position 6,166,867 counting from the first digit after the decimal point. The 3. is not counted.

The string and surrounding digits:

13137431811835557317 026516 17821568519288377669

All I can say is WOW. I wish I had seen this thread sooner!

"Guardian Angels, I request a Most Benevolent Outcome for each of us winning the lottery on this day and may the outcome be a gazillion times better than I could hope for or expect and may it happen in ways for the highest and best good of me and everyone else concerned. Thank You, I Receive."
onlymoney

United States
Member #128,782
June 2, 2012
5,431 Posts
Offline

Nov 4, 2012, 4:49 pm

Quote: Originally posted by msjthewinner on Nov 4, 2012
Ok, just came across this thread and tried it for NC - I used the

last 2 draws as input: 026516

11/3/12 Day - 026

11/3/12 Eve - 516

Hitting the "find next" button 5 times gave today's midday (11/4/12)

number as an exact match 837

The string 026516 occurs at position 6,166,867 counting from the first digit after the decimal point. The 3. is not counted.

The string and surrounding digits:

13137431811835557317 026516 17821568519288377669

All I can say is WOW. I wish I had seen this thread sooner!

Wow, you just gave me an idea. I've already done what you did with no regular results, but guess what I just did.

I wanted to see how far past the original string before I saw the next winning number STRAIGHT, so I copied and pasted the string after the two combos and kept doing this over and over until I saw the straight winning number.

My first test i got it on the fifth "find next" The second one was on the third next find hit.

Florida,

Novemebr 2 mid-539 eve-880

November 3 mid-805

So I input 539880 into the search box.

12289731225045019397 539880 19599295859466744488----copy and paste the blue part into the search box.

31225045019397539880 19599295859466744488 52792346410372473341----do this again.

19599295859466744488 52792346410372473341 35338390259480773955----do it again.

52792346410372473341 35338390259480773955 17640674147646580145----do it again.

35338390259480773955 17640674147646580145 33037551258783915206----do it again, last time.

And voila, 17640674147646580145 33037551258783915206 00273054598058280083

A total of 90 combos for a straight hit.

I have to do more tests to see if this is profitable.

The next example was much shorter.

Novemebr 2 eve-880

November 3 mid-805 eve-473

Input 880805

15441620604831779602 880805 07865255635486975728

20604831779602880805 07865255635486975728 12807009365139201179

07865255635486975728 12807009365139201179 35423937582506047223

12807009365139201179 35423937582506047223 88473213403160556950

A total of 54 combos for a straight hit.

Now i have to go to work to see if this happens as often as I like. This would be great for online payouts.

onlymoney

United States
Member #128,782
June 2, 2012
5,431 Posts
Offline

Nov 5, 2012, 2:20 pm

Well I tried a little experiment today and it worked. Unfortunately I didn't play for real, meaning I would've won 500 bucks. Oh well, chalk it up to experience. The winning number can be seen in the link below.

United States Member #128800 June 2, 2012 1214 Posts Online

Posted: Today, 8:14 am - IP Logged

Reply Favorites

Mid,

480-481-482-483-484-485-486-487-488-489

050-051-052-053-054-055-056-057-058-059

https://www.lotterypost.com/thread/252627/2773595

I inputted both mid and eve from Florida yesterday into the search box. I then eliminated all the duplicate numbers in the red portion. I did this because I noticed in a short test that a lot of the times I'll get two out of three numbers on either ends of the string, but I wanted to first eliminate the dupes so i can deal with less numbers.

October 4 mid-983 eve-916

October 5 mid-058

983916

43030554358794396727 983916 05502135148333240544

Duplicates removed from red string leaves: 0521348

The ends of the strings is where I see pairs leaves: 052 and 348.

Next, I look at lakerben's sums to pairs chart and see what 983 and 916 produce as far as pairs, and for 983 we got a sum of 20=62 and 63 pairs. And 916 sum of 16=49 and 50 pairs.

1= 2 x
2=5 x
3=8 x
4=11 12
5=15 16
6=18 19
7=21 22
8=24 25
9=27 28
10=30 31
11=34 35
12=37 38
13=40 41
14=43 44
15=46 47
16=49 50
17=52 53
18=56 57
19=59 60
20=62 63
21=65 66
22=68 69
23=71 72
24=74 75
25=77 78
26=81 82
27=84 85

So why did I pick the 50 and 48 pairs? I did because I remembered and old system, I believe it was the "Panther" system where you look for repeating pairs within a 14 day period. If you see two pairs within a 14 day period, there's a good chance they'll repeat for at least a 3rd time before the end of the 14 day period.

Below is the history of the last 14 day period in Florida. As you can see, the "05" pair showed twice before today's midday draw in red below, and i was hoping it would show for the third time, which it did in today's mid draw.

I also picked the pair "48" for the same reason as the 05 pairs. The 48 pair also showed up twice in the past 14 days in green below.

Oct. 22, 260 161

Oct. 23, 664 799

Oct. 24, 423 148

Oct. 25, 953 246

Oct. 26, 576 809

Oct. 27, 152 128

Oct. 28, 554 327

Oct. 29, 690 055

Oct. 30, 295 646

Oct. 31, 002 534

Nov. 01, 877 448

Nov. 02, 539 880

Nov. 03, 805 473

Nov. 04, 983 916

Nov. 05, 058

You may be wondering why I didn't use the other 3 pairs from lakerben's chart, 49-62 and 63. Those pairs didn't have any repeats withing the last 14 days.

And the 48 pair just stuck out in my face as I was examining the past history 14 days.

Of course this won't work everytime, but I believe this method is one of the best ways to narrow your numbers down to an affordable cost while that straight hit comes along.

onlymoney

United States
Member #128,782
June 2, 2012
5,431 Posts
Offline

Nov 5, 2012, 5:23 pm

WOW!

Check this out peeps!!!!!

I was looking for different ways to enter numbers into the search box and found something very interesting. I was getting straight hist with either ONE ticket to purchase or upt to 27, or a little more tickets.

Instead of inputting numbers horizontally, I tried it vertically and it was giving me staright numbers, sometimes without even hitting the "Find next" button, and sometimes just a couple of clicks away. WOW !

Oct. 22, 260 161

Oct. 23, 664 799

Oct. 24, 423 148

Oct. 25, 953 246

Oct. 26, 576 809

Oct. 27, 152 128

Oct. 28, 554 327

Oct. 29, 690 055

Oct. 30, 295 646

Oct. 31, 002 534

Nov. 01, 877 448

Nov. 02, 539 880

Nov. 03, 805 473

Nov. 04, 983 916

Nov. 05, 058

===================================================

Input the numbers in red into the search box and we get the following:

Look at the next number after 8589. It's a 0. That's the first number of today's florida midday winner 058.

8589=68092087476091782493 8589 00971490967598526136

Now we input the numbers in blue into the search box. 7308

7308=20317448719540397610 7308 06026990625807602029, we get no winning number, it's a 0. But watch what happens when I hit "find Next". 40918938945576768749 7308 56955958010659526503, we get our 5 for the middle spot in 058.

Now we input the third vertical row, on the fourth click, 7953. 09479138180406328738 7593 84826953558307739576, we get our third number 8 in 058.

NOW, REMEMBER IN THIS METHOD, WE USE THE FIRST NUMBER EVEN BEFORE WE CLICK ON THE "FIND NEXT" BUTTON. SO WHEN I SAY THE FOURTH CLICK OF THE NEXT FIND BUTTON, IT'S REALLY FIVE CLICKS BECAUSE WE ARE USING THE FIRST NUMBER BEFORE THE FIRST CLICK.

Nov. 01, 877 448

Nov. 02, 539 880

Nov. 03, 805 473

Nov. 04, 983 916

Nov. 05, 058

So, to recap, the first number we got before we even hit the find next button. The second number we got on the first click of the find next button, and the third number we got on the fourth click. The cost would look like below:

0 0 8

5 2

8 ----duplicate, so we eliminate.

6

5

New version after the elimination of the second 8 below:

0 0 8

5 2

6

5

Cost: 8 bucks

Breakdown, first column is 0, so it's 1X2, 2 for the next column X 4 for the next column equals 8. 1X2=2, 2X4=8

I've seen a few that have all three winning numbers before I even click on the find next button. And some have either 2 or 3 clicks before I get a win.

So as a rule, I will test just the first 3 numbers I get, meaning the first time I click on "show PI" button counts as the first number, and the "find next" button counts as the second number.

So for tonight's florida experiment I will use the first 3 numbers I get per column for a total cost of 27 dollars. Remember, if you get any duplicates in the same column, hit the find next button to get a new number.

Nov. 01, 877 448

Nov. 02, 539 880

Nov. 03, 805 473

Nov. 04, 983 916

Nov. 05, 058

First column: 4849

Second column:4871

Thrid column: 8036

Results:

3 7 8

4 9 7

1 8 2

Combinations:

378-377-372-398-397-392-388-387-382

478-477-472-498-497-492-488-487-482

178-177-172-198-197-192-188-187-182

Remember, I've done about 5 or 6 days test in Florida, and never did I go over 5 on any one column, in fact, in the winners I found, only 1 or 2 test dates did I even have to go as far as 4 or 5 tops. So this may be the new money maker. It doesn't have to hit everytime to make a nice profit especially if played online.

Test this in your state and let me know.
onlymoney

United States
Member #128,782
June 2, 2012
5,431 Posts
Offline

Nov 6, 2012, 11:06 am

Midday Florida test,

0 7 8

1 6 1

4 3 0

078-071-070-068-061-060-038-031-030

178-171-170-168-161-160-135-130

478-470-470-468-461-460-438-431-430

New Topic New Poll

Subscribe to this topic

Man finds winning numbers in strings of PI (Video)Prev TopicNext Topic

Man finds winning numbers in strings of PI (Video)Prev Topic Next Topic