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Just heard Lottery Preys on the PoorReply
Thr lottery preys on everyone looking for a small chance at hitting it big against high odds of losing frequently...if they don't understand what they're doing. Wealthy and/or well off people lose on the lottery as well...it doesn't discriminate at all. What separates the two is how well they apply their knowledge, stategies, monies, and patience towards these games. It requires the right balance of all these to be successful at winning...at least with the Pick 3/4 games. No one, be it rich or p
Jul 9, 2012, 7:50 pm - Lucky Loser - Lottery Discussion Forum

NAACP wants Texas Lottery shut downReply
I see this as a cluster of problems on many levels...and compounded. First, lottery games are designed to generate income, and thus, more people must lose than win. Also, this must happen frequently which is partly where odds are derived from. Losses are pre-determined and calculated for the most part. Some players understand this, but most people don't and they gamble with their food or bill money in hopes of getting lucky and becoming free of a present living condition or style. I do agree
Jun 30, 2012, 12:26 am - Lucky Loser - Lottery News

Do some number combinations have better odds?Reply
With all due respect RJ, your post sounds quite random and even a little spastic. Until this post (in response to no one) nobody has talked about winning a JP here. The thread subject matter is clearly Do some number combinations have better odds? 3 posts in front of your I clearly reiterated (again) that those of us participating in this thread are doing TRIALS to prove that some number conbinations have BETTER odds. Which has nothing to do with winning a JP. Although I do hope
Jun 29, 2012, 4:07 pm - Ronnie316 - Lottery Discussion Forum

Do some number combinations have better odds?Reply
You hit two draws? In a row? Where? I also don't see where you came up with 1 in 200,000. The odds of winning two jackpots in a row with 100,000 lines are roughly one in 3 million. The odds of winning a 5/5 with 100,000 is about 1/40, and twice in a row about 1/1600. If you meant it only took two draws, then the odds are about 79/1600. (Very close to 2/40) Remember, you're talking to the guy who wrote down a set of numbers a little after turning 18, didn't play, and would
Jun 17, 2012, 5:22 pm - Boney526 - Lottery Discussion Forum

How can I be such a loser!!Reply
Stop playing Keno for a while and play something else, give it arrest. Have you compared the odds of an average Keno game to the 31.8 to 1 odds of winning something in PB or 39.9 to 1 in MM? Lots of people think the lotto eliminates previous numbers picked some how to there will not be a winner, They say 70% to 80% of PB purchases are QPs and so are the prize winners. Maybe some players do eliminate certain numbers, groups of numbers, high/low even/odd proportion, sums, etc., but th
Jun 12, 2012, 6:05 pm - Stack47 - Lottery Discussion Forum

RL's Digit Master Pro Big Game software download.Reply
If you browse your filesystem where the program is installed (on my system C:\DMP-BG\GAMES) you should find a file TEMP.TXT that is generated that has all the filter setting values for all the draws. Just eyeball this file and set the base ranges for your filters. Using these base settings you have thrown millions of combinations out. Then for each drawing do as RL has told you to eliminate a few digits and a few groups from these base settings and you should get down to a manageable set to play
Jun 3, 2012, 12:24 am - jimjwright - Lottery Systems Forum

Calculate odds for random pickingReply
your odds of doing this would probably be much worse then the actual odds of picking the correct number. Lets examine your premis. 1st you will pick 6 draws from the past 100 simple enough. 100*99*98*97*96*95/6*5*4*3*2*1 =7152314400. Then you have the problem of having 6 sets of 5 or 6 numbers to choice from discounting doubles. Its not really confusing on why you cant find the correct path. Your odds are against picking the correct answer and larger then just playing every combo.
May 2, 2012, 7:07 pm - nickbrownsfan - Mathematics Forum

Calculating odds for a subset of numbersReply
Num = Number of tickets you play out of 200,000 Set = Set of 200,000 super candidates Pct = Percent of times this super set has jackpot winning combo (0.75 or 75%) Odds = Num * Pct / Set extrema: let Num = 1, then odds of winning a jackpot become 1 in 266,666 let Num = 200,000, then odds of winning a jackpot become 1 in 1.333 (three out of four)
Apr 28, 2012, 2:03 am - time*treat - Mathematics Forum

Calculating odds for a subset of numbersReply
Yes, 879 to 1 makes sense but I'm not playing all 200K numbers(that would be nice though!). I'm trying to calculate my odds of picking the winner out of the 200K ticket pool if I play X number of tickets and I know the pool contains the winner 75% of the time. The odds are 200K to 1 at least if I play a single ticket but the part I'm not getting my head around is how the 75% changes things. Does it increrase the odds 25%? So instead of 200K to 1 on a single ticket it's now 250K
Apr 26, 2012, 4:48 pm - mega-mega - Mathematics Forum

Which odds are better?Reply
Your kidding right KY?? The cards themselves are NOT random, they are individually identified and NUMBERED 1-52. Lottery balls are in the same manor ordered and NUMBERED 1-56 in the instance of MM. When a person with a brain put a number 1 on a ball it was no longer a random ball, it was the fisrt in a ORDERED sequence of 56 in the case of MM. For you to think that 1,2,3,4,5 are random balls is more like insane. Or your living in an alternate universe where reality is whatever you want it
Apr 17, 2012, 11:17 am - Ronnie316 - Lottery Discussion Forum