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Buying more tickets = reduced oddsReply
I think the reason why some of us don't accept that as truly reducing odds is because to say 1:60,000,000 in the case of 2 pb tickets, is saying your one ticket that was once 1:120,000,000 is now 1:60,000,000, when in fact it's still 1:120,000,000 for each ticket. If they drew two sets of winning numbers, then looking at the odds that way would make more sense. The odds being expressed in the number of possible combinations against your ticket(s).
May 5, 2004, 2:21 pm - wiseone2 - Lottery Discussion Forum

Buying more tickets = reduced oddsReply
Quote: Originally posted by keystonechas on May 04, 2004Unless your talking pick 3 or pick 4 games where payouts are set, any calculations at buying more tickets to reduce the odds is useless. As wiseone2 stated your dealing with a parimutuel game. Number of winning tickets sold divided by the jackpot.So why bother with ticket reduction odds?ChasCan anyone answer my orginal question? Why bother with ticket reduction odds if your dealing with a parimutuel game?Chas
May 4, 2004, 8:13 pm - keystonechas - Lottery Discussion Forum

Buying more tickets = reduced oddsReply
the only example that clearly reflects reducing odds with the number of tickets purchased formula, is when you purchase half of the possible outcomes of a drawing. You have a 50% chance of winning. But in the case of the pick 3 straight combo paying $500, would investing $500 to reduce your odds in half, and having one of your 500 numbers drawn winning ? No, it's just a break even prize. Odds are normally figured with the inclusion of break even prizes. In another scenario, assume ever
May 4, 2004, 4:43 pm - wiseone2 - Lottery Discussion Forum

Buying more tickets = reduced oddsReply
Todd, in your example of buying two tickets in a game with odds of 1:1000, you are correct in that if you bought two tickets, it will equal 2:1000, but it does not reduce the odds in half, obviously. Odds are expressed in ratios. The definition of a ratio is a fraction expressed in its lowest terms. That is the rule. So no matter how many tickets you buy, the 1000 portion of the ratio stays the same, does not change. So in a game where the odds ratio is X:1000, X is the number of tickets p
May 4, 2004, 2:31 am - wiseone2 - Lottery Discussion Forum

Buying more tickets = reduced oddsReply
Quote: Originally posted by Jake649 on May 03, 2004This topic came up in another thread but the thread went off in a tangent so I decided to start a new thread devoted to the following questions.Q: Can lottery odds be reduced by buying more tickets?A: YesQ: How are the new, reduced odds calculated?A: Say that a lottery has X number of unique outcomes. Then the odds of hitting the jackpot is 1 in X. If one buys N number of tickets where no two tickets have exactly the same set of numbers, then th
May 3, 2004, 9:32 pm - prob987 - Lottery Discussion Forum

Predictions - Are You Serious ?Reply
Jake,Thanks for motivating me to consider the problem of odds and wheeling. As we discussed, I have an intuitive sense that restricted wheeling lowers one odds with multiple tickets. Still, your response at first set me back a bit, because of your statement about the odds for the second ball being higher in a wheel.I have now a better, more formal demonstration of why restrictive wheeling reduces odds overall, consistent with my intuitive feeling. I'm pretty busy right now and don't have time
May 3, 2004, 9:21 pm - prob987 - Lottery Discussion Forum

Question About Buckeye 5
The listed odds of this game are 435,897:1. Has anyone been able to reduce these odds? I could've sworn I read a posting a while back where someone said they got it down to about 100,000:1. Is that accurate? Can anyone confirm this? I'm just wondering what the real odds are that I'm up against. Thanks.ToddPlatinum298
May 3, 2004, 1:56 am - Platinum298 - Lottery Discussion Forum

Predictions - Are You Serious ?Reply
Quote: Originally posted by Jake649 on May 02, 2004Quote: Originally posted by prob987 on May 02, 2004At the moment just before the first white ball is drawn you will have in the non-repeating set, a probability of 10 in 53 of having one number in either ticket. In the second set, sharing one number, you will have a probability of only 9 in 53 of having one number in either ticket. This means that you have an 18.9% of remaining in the game in the first case, and a 17.0% chance of remaining in
May 2, 2004, 7:27 pm - prob987 - Lottery Discussion Forum

Predictions - Are You Serious ?Reply
I know that lottery numbers cannot be predicted. If they could be predicted all of the lotteries would go out of business rather quickly. That said, a predicted number is as likely to win as is any other number. If one likes to predict, there is no harm in it.Certainly there are some lottery winners who will tell everyone that they predicted their wins. Of course, there are also lots of people who won with quick-picks. Neither class of winners proves that one type of playing is b
May 1, 2004, 10:32 pm - prob987 - Lottery Discussion Forum

Wow! Second 4 of 6 in a row! (NJ Pick 6)Reply
Well Todd, your odds of winning twice in a row (assuming just one ticket for each drawing) are worse than 1 in a million, 1 in 1,065,024 to be exact. On one hand, you won, so no problem there, but on the other hand, for beating odds that large, one might have wished for a bigger payoff.Your experience demonstrates what all lottery players hope for though, that long odds can be beaten.
Apr 26, 2004, 12:18 pm - prob987 - Jackpot Games Forum