Ultra-34 P-3-P-4 softwarePrev Topic Next Topic

New Topic New Poll

RL-RANDOMLOGIC

United States
Member #59,352
March 13, 2008
5,626 Posts
Offline

Jun 29, 2019, 9:01 pm

adobea78

When using base-4 or the rogues as I call them the first step is to raise 4 to the power of y until

the result is >= the matrix. For pick-3 it's 4^5 which equals 1024 and 4^7 for pick 4. Any value

above the matrix is a rogue which is never used.

4^1=4, 4^2=16, 4^3=64, 4^4=256 and 4^5=1024. Rogues are always divisible by 4 and the

first rogue value represents the greatest value <= the matrix. For pick-3 this value is 256. Lets

look at the set 570. To get the first rogue value we divide 570 / 256 =2 with a remainder of

256*2=512 and 570-512 = 58 as the remainder, Rogue-A=2. Next we drop down to 4^4=64

and 58 / 64 < 1 so Rogue-B=0. Next we drop down to 4^2=16 and 58/16=3 with a remainder of

10, Rogue-C = 3. Next we drop down to 4^1 = 4 and 10/4=2 with a remainder of 2, Rogue-D= 2.

The last rogue value will always be <=3 which is the last rogue, in this case 2. So 570=20322.

To reverse the process

2*256=512

0*64 = 0

3*16 = 3

2*4 =8

1*2=2

20322 = 512+0+8+2=570.

base-2

0=0

1=1.

00=0

01=1

10=2

11=3.

000=0

001=1

010=2

100=3

101=4

110=5

111=6

Base 4 will always be divisible by 4 with the final remainder being the final rogue value.

Pick-4 requires 4^7= 16384 and 4^6=4096 which is our first step for this game then 4^5,

4^4, 4^3,4^2,4^1.

4096

512

64

16

4

1

RL

....
thamizhpayan

United States
Member #173,008
February 13, 2016
1,637 Posts
Offline

Jun 29, 2019, 9:23 pm

Quote: Originally posted by RL-RANDOMLOGIC on Jun 29, 2019
adobea78

When using base-4 or the rogues as I call them the first step is to raise 4 to the power of y until

the result is >= the matrix. For pick-3 it's 4^5 which equals 1024 and 4^7 for pick 4. Any value

above the matrix is a rogue which is never used.

4^1=4, 4^2=16, 4^3=64, 4^4=256 and 4^5=1024. Rogues are always divisible by 4 and the

first rogue value represents the greatest value <= the matrix. For pick-3 this value is 256. Lets

look at the set 570. To get the first rogue value we divide 570 / 256 =2 with a remainder of

256*2=512 and 570-512 = 58 as the remainder, Rogue-A=2. Next we drop down to 4^4=64

and 58 / 64 < 1 so Rogue-B=0. Next we drop down to 4^2=16 and 58/16=3 with a remainder of

10, Rogue-C = 3. Next we drop down to 4^1 = 4 and 10/4=2 with a remainder of 2, Rogue-D= 2.

The last rogue value will always be <=3 which is the last rogue, in this case 2. So 570=20322.

To reverse the process

2*256=512

0*64 = 0

3*16 = 3

2*4 =8

1*2=2

20322 = 512+0+8+2=570.

base-2

0=0

1=1.

00=0

01=1

10=2

11=3.

000=0

001=1

010=2

100=3

101=4

110=5

111=6

Base 4 will always be divisible by 4 with the final remainder being the final rogue value.

Pick-4 requires 4^7= 16384 and 4^6=4096 which is our first step for this game then 4^5,

4^4, 4^3,4^2,4^1.

4096

512

64

16

4

1

RL

Hi RL,

Pick 3 : 4*4*4*4*4=1024 5 rogue digits with all 5 positions with 4 digits(0-3)

24 sets will be empty in 00000-33333 : in the permutations

Pick 4 : 3*4*4*4*4*4*4=12288 7 rogue digits with 1st leading position just 3 digits(0-2) rest 6 positions with 4 digits(0-3)
2288 sets will be empty in 0000000 - 3444444 : in the permutations

Is this correct?

Thanks
RL-RANDOMLOGIC

United States
Member #59,352
March 13, 2008
5,626 Posts
Offline

Jun 29, 2019, 10:09 pm

Correction

100=3 should be 011

101=4 should be 100

110=5 should be 101

Sorry for the mistake, the wife was trying to draw me out the door to go get tickets.

RL

....
adobea78

United States
Member #116,337
September 8, 2011
5,179 Posts
Offline

Jun 29, 2019, 10:26 pm

Quote: Originally posted by RL-RANDOMLOGIC on Jun 29, 2019
adobea78

When using base-4 or the rogues as I call them the first step is to raise 4 to the power of y until

the result is >= the matrix. For pick-3 it's 4^5 which equals 1024 and 4^7 for pick 4. Any value

above the matrix is a rogue which is never used.

4^1=4, 4^2=16, 4^3=64, 4^4=256 and 4^5=1024. Rogues are always divisible by 4 and the

first rogue value represents the greatest value <= the matrix. For pick-3 this value is 256. Lets

look at the set 570. To get the first rogue value we divide 570 / 256 =2 with a remainder of

256*2=512 and 570-512 = 58 as the remainder, Rogue-A=2. Next we drop down to 4^4=64

and 58 / 64 < 1 so Rogue-B=0. Next we drop down to 4^2=16 and 58/16=3 with a remainder of

10, Rogue-C = 3. Next we drop down to 4^1 = 4 and 10/4=2 with a remainder of 2, Rogue-D= 2.

The last rogue value will always be <=3 which is the last rogue, in this case 2. So 570=20322.

To reverse the process

2*256=512

0*64 = 0

3*16 = 3

2*4 =8

1*2=2

20322 = 512+0+8+2=570.

base-2

0=0

1=1.

00=0

01=1

10=2

11=3.

000=0

001=1

010=2

100=3

101=4

110=5

111=6

Base 4 will always be divisible by 4 with the final remainder being the final rogue value.

Pick-4 requires 4^7= 16384 and 4^6=4096 which is our first step for this game then 4^5,

4^4, 4^3,4^2,4^1.

4096

512

64

16

4

1

RL

RL,

Thanks, reminds me of binary conversion of octet in IP address in my A+ course years ago. Now with reduction to just 256 picks, don't you think focus should be on only first and second positions of the rogue values ( a and b)?.
RL-RANDOMLOGIC

United States
Member #59,352
March 13, 2008
5,626 Posts
Offline

Jun 29, 2019, 11:03 pm

Quote: Originally posted by thamizhpayan on Jun 29, 2019
Hi RL,

Pick 3 : 4*4*4*4*4=1024 5 rogue digits with all 5 positions with 4 digits(0-3)

24 sets will be empty in 00000-33333 : in the permutations

Pick 4 : 3*4*4*4*4*4*4=12288 7 rogue digits with 1st leading position just 3 digits(0-2) rest 6 positions with 4 digits(0-3)
2288 sets will be empty in 0000000 - 3444444 : in the permutations

Is this correct?

Thanks

Base-4 requires everything before the last remainder to be divisible by 4. The last digit in the rogue

string is the remainder of the conversion.

Pick-3 = 4*4*4*4*4 = 1024

Pick-4 = 4*4*4*4*4*4*4=16,384

5-39 = max-index 575,757 = 4*4*4*4*4*4*4*4*4*4=1,048,576

PB 5-69 max-index = 11,238,513 = 4*4*4*4*4*4*4*4*4*4*4*4=16,777,216

Because we must maintain a power of 4 as the base there will almost always be a remainder, the values

above the number of lines in the matrix, this is where name rogues come from.

Take P-4 for example, 4^6=4,096 so the next available is 4^7= 16,384. We all know that a pick-4

only has 10K lines but base-4 is based on 4^y. The only difference between a daily game version of

the rogues and number games is that in number games the number set is converted to it's lex-index

before it's converted to a rogue. It takes a 10 digit rogue string to convert my 5-39. My algorithms

are very fast and can make around 5000 conversions per. Set-to-lex, Lex-to-Rogue, Rogue-to-Lex

etc...

The first step in the conversion will almost always start with the base power -1 so for pick-4 this means

that it will be 4^6=4096 as 4^7 is greater than the matrix. If the first rogue digit is 2 then we start with

2*4096=8192, which means that the actual set will fall within the range of 8192 to 9999. This is also the

reason there are no digit 3s in Rogue-A as 3*4096=12,288 which is above 10K. Each additional rogue

value that is set narrows down the range of possible sets and setting all 7 reduces to a single line. Think

of the rogue of as a 7 digit address of sorts where digits 0-1-2-3 are the only options.

Notice in pick-3

setting 4 of 5 positions produces 4 lines

setting 3 of 5 positions produces 16 lines

setting 2 of 5 positions produces 64 lines

setting 1 of 5 positions produces 256 lines

setting 0 of 5 positions produces 1000 lines, the process stops at 999 so the others are of no concern.

RL

....
RL-RANDOMLOGIC

United States
Member #59,352
March 13, 2008
5,626 Posts
Offline

Jun 29, 2019, 11:32 pm

adobea78

It's computer logic 101, just with a different spin. In the number game versions it's important to

work out the rogue positions starting with A and work down. Sometimes hitting the first 3 values

will produce a match-3 regardless of how many of the remaining are set incorrectly. When playing

daily games I am not sure where we start is important as there are no second level prizes. Some

games do offer playing front, back pairs or when playing box it could have a positive effect. I play

my 5-39 but to stay with this topic I split the 5-39 index into two pick 3 databases. The front lex

is a little easier because the 5-39 matrix has 575,757 total lines so working with it, the range is 000

to 575, a little over half the lines of a normal pick 3. The wife takes the front 3 and I take the back 3.

We each pick 4 rogue strings which when combined produces 16, 5-39 lines. I have a number game

version but to keep with the topic here I play my 5-39 as two pick 3s.

RL

....
adobea78

United States
Member #116,337
September 8, 2011
5,179 Posts
Offline

Jun 29, 2019, 11:36 pm

Quote: Originally posted by RL-RANDOMLOGIC on Jun 29, 2019
Base-4 requires everything before the last remainder to be divisible by 4. The last digit in the rogue

string is the remainder of the conversion.

Pick-3 = 4*4*4*4*4 = 1024

Pick-4 = 4*4*4*4*4*4*4=16,384

5-39 = max-index 575,757 = 4*4*4*4*4*4*4*4*4*4=1,048,576

PB 5-69 max-index = 11,238,513 = 4*4*4*4*4*4*4*4*4*4*4*4=16,777,216

Because we must maintain a power of 4 as the base there will almost always be a remainder, the values

above the number of lines in the matrix, this is where name rogues come from.

Take P-4 for example, 4^6=4,096 so the next available is 4^7= 16,384. We all know that a pick-4

only has 10K lines but base-4 is based on 4^y. The only difference between a daily game version of

the rogues and number games is that in number games the number set is converted to it's lex-index

before it's converted to a rogue. It takes a 10 digit rogue string to convert my 5-39. My algorithms

are very fast and can make around 5000 conversions per. Set-to-lex, Lex-to-Rogue, Rogue-to-Lex

etc...

The first step in the conversion will almost always start with the base power -1 so for pick-4 this means

that it will be 4^6=4096 as 4^7 is greater than the matrix. If the first rogue digit is 2 then we start with

2*4096=8192, which means that the actual set will fall within the range of 8192 to 9999. This is also the

reason there are no digit 3s in Rogue-A as 3*4096=12,288 which is above 10K. Each additional rogue

value that is set narrows down the range of possible sets and setting all 7 reduces to a single line. Think

of the rogue of as a 7 digit address of sorts where digits 0-1-2-3 are the only options.

Notice in pick-3

setting 4 of 5 positions produces 4 lines

setting 3 of 5 positions produces 16 lines

setting 2 of 5 positions produces 64 lines

setting 1 of 5 positions produces 256 lines

setting 0 of 5 positions produces 1000 lines, the process stops at 999 so the others are of no concern.

RL

RL,

It will be nice if the 1024 lines rogues can be charted ,
RL-RANDOMLOGIC

United States
Member #59,352
March 13, 2008
5,626 Posts
Offline

Jun 29, 2019, 11:38 pm

adobea78

Not sure but I think winsum has already done it.

RL

....
adobea78

United States
Member #116,337
September 8, 2011
5,179 Posts
Offline

Jun 29, 2019, 11:48 pm

Quote: Originally posted by RL-RANDOMLOGIC on Jun 29, 2019
adobea78

Not sure but I think winsum has already done it.

RL

I will check it.

I need to wheel 4⁵

00000

11111

22222

33333
thamizhpayan

United States
Member #173,008
February 13, 2016
1,637 Posts
Offline

Jun 30, 2019, 4:26 am

Thanks RL for the detailed explanation.

It's like quadrant fractal or peeling/unwraping quadrants.

Yes you have nice algorithm deriving math brain. For Lexi to Combo and Combo to Lexi I use the code from one of the Combinatorics books code.

I like the conversion timings.

I am also experimenting with T-Lex and was looking for your 10 Tools collection. Those were posted long before I joined.
RL-RANDOMLOGIC

United States
Member #59,352
March 13, 2008
5,626 Posts
Offline

Jun 30, 2019, 11:27 am

Quote: Originally posted by thamizhpayan on Jun 30, 2019
Thanks RL for the detailed explanation.

It's like quadrant fractal or peeling/unwraping quadrants.

Yes you have nice algorithm deriving math brain. For Lexi to Combo and Combo to Lexi I use the code from one of the Combinatorics books code.

I like the conversion timings.

I am also experimenting with T-Lex and was looking for your 10 Tools collection. Those were posted long before I joined.

I recently found the source code for one of the old tool boxes that was uploaded back in 2013, or 2014.

It contains code for several tools, a file-converter, lex-index wheel, mini-lex generator and a few others.

I may repackage it and place it for download in the near future. I also remember a file splitter but it was

not in the old folder but it should be easy to whip one up.

RL

....
lakerben

50

New Mexico
United States
Member #86,094
January 29, 2010
30,576 Posts
Offline

Jun 30, 2019, 11:33 am

Great!!! Thanks for everything!

Win!
CARBOB

COLUMBUS,GA.
United States
Member #4,924
June 3, 2004
6,719 Posts
Offline

Jun 30, 2019, 11:43 am

Ga Mid 06/30/19

32132 926
winsumloosesum

Philadelpia/Pennsylvania
United States
Member #2,218
September 1, 2003
6,928 Posts
Online

Jun 30, 2019, 11:55 am

Quote: Originally posted by RL-RANDOMLOGIC on Jun 30, 2019
I recently found the source code for one of the old tool boxes that was uploaded back in 2013, or 2014.

It contains code for several tools, a file-converter, lex-index wheel, mini-lex generator and a few others.

I may repackage it and place it for download in the near future. I also remember a file splitter but it was

not in the old folder but it should be easy to whip one up.

RL

I added download links to the Tools programs you shared in 2014 or so. There were also some of your videos.

Also added the D-TRAP program which was an updated program. There was an older D-TRAP included in the Tools programs.

I'm not sure if these are the same you are considering re-sharing.
thamizhpayan

United States
Member #173,008
February 13, 2016
1,637 Posts
Offline

Jun 30, 2019, 11:56 am

Quote: Originally posted by RL-RANDOMLOGIC on Jun 30, 2019
I recently found the source code for one of the old tool boxes that was uploaded back in 2013, or 2014.

It contains code for several tools, a file-converter, lex-index wheel, mini-lex generator and a few others.

I may repackage it and place it for download in the near future. I also remember a file splitter but it was

not in the old folder but it should be easy to whip one up.

RL

Hi RL,

Thanks.

I was going through some old threads and came across those.

RL'S TOOLS
Three digit tools will be installed, D-Calc, D-Trap and DNWSA https://www.lotterypost.com/thread/275061/3802818
Instructions video https://www.lotterypost.com/thread/275061/3802828

9-Tools https://www.lotterypost.com/thread/275061/3836238
Instruction videos in the same link

10-Tools https://www.lotterypost.com/thread/275061/3849570
Instruction videos in the same link

Please take your time and package & share those when you get time. I was particularly interested in the wheels as I needed some standalone wheels for Big Games.

Thanks

New Topic New Poll

Subscribe to this topic

Ultra-34 P-3-P-4 softwarePrev TopicNext Topic

Ultra-34 P-3-P-4 softwarePrev Topic Next Topic